The idea is to divide the force by the mass (according to Newton's Second Law). The answer will be in meters/second2.
The acceleration of the car can be calculated using the formula: acceleration = force / mass. Plugging in the given values: acceleration = 4000 N / 1000 kg = 4 m/s^2. Therefore, the car's acceleration when braking is 4 m/s^2.
To find the acceleration, use Newton's second law: F = ma, where F is the net force, m is the mass, and a is the acceleration. Rearranging the formula to solve for acceleration gives a = F/m. Plugging in the values F = 4000 N and m = 1000 kg, the acceleration of the car is 4 m/s^2.
It is 0 N because it's moving at a constant velocity so the acceleration would be 0. Net Force = m x a so Net Force = 1850 kg x 0 m/s/s
The net force on the barrel is the difference between the force of the barrel and the force of the pavement: 6000 N - 2000 N = 4000 N. Therefore, the net force on the barrel as it hits the pavement is 4000 N.
Use the formula: Force = mass x acceleration. Since you are using standard SI units, the answer will be in Newtons.Use the formula: Force = mass x acceleration. Since you are using standard SI units, the answer will be in Newtons.Use the formula: Force = mass x acceleration. Since you are using standard SI units, the answer will be in Newtons.Use the formula: Force = mass x acceleration. Since you are using standard SI units, the answer will be in Newtons.
The acceleration of the car can be calculated using the formula: acceleration = force / mass. Plugging in the given values: acceleration = 4000 N / 1000 kg = 4 m/s^2. Therefore, the car's acceleration when braking is 4 m/s^2.
24000 = 20000 + 4000 in expand form
24000
To find the acceleration, use Newton's second law: F = ma, where F is the net force, m is the mass, and a is the acceleration. Rearranging the formula to solve for acceleration gives a = F/m. Plugging in the values F = 4000 N and m = 1000 kg, the acceleration of the car is 4 m/s^2.
The interest is 300% per year.
It is 0 N because it's moving at a constant velocity so the acceleration would be 0. Net Force = m x a so Net Force = 1850 kg x 0 m/s/s
5000 psi. you stupid inbred
If that is 4000N of normal force (?) assuming its just at rest with that normal force, then the force of gravity is equal to the normal force Fg=4000 Fg=mg 4000=m(10) 4000/10=m m=400kg GPE=mass(acceleration due to gravity)height GPE=400kg(10m/second squared)12m GPE=48,000 Joules W=E1+E2 E1=0 E2=48,000 W=48,000 I'm pretty sure that's right. Somewhat correct me if it isn't.
it cost 4000
The net force on the barrel is the difference between the force of the barrel and the force of the pavement: 6000 N - 2000 N = 4000 N. Therefore, the net force on the barrel as it hits the pavement is 4000 N.
with a cessna 152 a 2 seater it will cost about £4000 a year
A femur bone can withstand roughly 4000 N of force.