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A force of 800 newtons is needed to push a car across a lot 2 students push the car 40 meters How much total work do both students do?
Work done = Force x distance moved in the direction of force So work done = 15 x 20 = 300 joule That force 15 newton would be the necessary and equivalent force to overcome the static frictional force. Static frictional force depends, of course, on the mass of the box.
A force of 20 newtons is required to push a cart weighing 30 newtons 40 meters across a room. From this effort how many joules of work are performed?
A force of 20 newtons acting through a distance of 40 meters produceswork equal to (20 x 40) = 800 newton-meters = 800 joules.The weight of the cart doesn't matter.
What is the Acceleration of the North American Eagle Land Speed Car?
The North American Eagle Land Speed Car has a top speed of over 800 km/h (500 mph) and can accelerate at a rate of approximately 2G, which is equivalent to double the force of gravity.
What is the net force on a dragster with a mass of 900 kg if its acceleration is 32.0 ms squared?
f=m*a f=800*31 f=24 800 newtons if applied for 1 second(t) from zero, distance travelled(s) = 15.5 metres power =( f*s)/t =( 24800*15.5)/1 = 384 400 watts (about 516 bhp at drive wheels)
What force exert by parachutes?
Drop any object from a plane and the downward force due to the mass will eventually be matched by an upward force due to air resistance (terminal velocity). This terminal velocity depends on the objects drag coefficient, what the parachute does is present a drag coefficient sufficient to give the required terminal velocity for landing . > You need no more than say 6 metres / second landing velocity, effectively this is the terminal velocity with the chute open. Using body mass of 80 kg and acceleration due to gravity of 10 (m/s)/s, this gives a downward force of ( 80 * 10 ) 800 newtons. To balance this at landing velocity, you need a drag coefficient calculated from: 800 = velocity2 * drag coefficient , so: drag coefficient = 800 / velocity2 = 22.22 > Compare this to the pre chute deployment velocity of around 80 metres / second, giving a drag coefficient of: drag coefficient = 800 / 6400 = 0.125
A 1000 kg automobile is pulled by a horizontal tow line with a force of 800 N What is the automobile's acceleration?
F = m aa = F/m = (800) / (1,000) = 0.8 m/sec2
What is the resulting acceleration when a 800 N force acts on an object with a mass of 7000 kg?
Just divide the force by the mass. The answer will be in meters per square second.
A force of 800 newtons is needed to push a car across a lot 2 students push the car 40 meters How much total work do both students do?
Work done = Force x distance moved in the direction of force So work done = 15 x 20 = 300 joule That force 15 newton would be the necessary and equivalent force to overcome the static frictional force. Static frictional force depends, of course, on the mass of the box.
When a 40 N force is applied to a mass of 2 kg what is the acceleration?
F = M a a = F / M = (800) / (2,000) = 0.4 meters per second2
A force of 20 newtons is required to push a cart weighing 30 newtons 40 meters across a room. From this effort how many joules of work are performed?
A force of 20 newtons acting through a distance of 40 meters produceswork equal to (20 x 40) = 800 newton-meters = 800 joules.The weight of the cart doesn't matter.
What is the Acceleration of the North American Eagle Land Speed Car?
The North American Eagle Land Speed Car has a top speed of over 800 km/h (500 mph) and can accelerate at a rate of approximately 2G, which is equivalent to double the force of gravity.
Two forces one 500 gf and the other 800gf act upon a body what are the maximum and minimum possible values of the resultant force?
If the act together (in the same direction), the resultant force is the sum - 1300 gf (whatever that abbreviation means!). This is the maximum. If they act in opposite directions, the resultant force is the difference, 300 gf - and this is the minimum.
What is the net force on a dragster with a mass of 900 kg if its acceleration is 32.0 ms squared?
f=m*a f=800*31 f=24 800 newtons if applied for 1 second(t) from zero, distance travelled(s) = 15.5 metres power =( f*s)/t =( 24800*15.5)/1 = 384 400 watts (about 516 bhp at drive wheels)
What force exert by parachutes?
Drop any object from a plane and the downward force due to the mass will eventually be matched by an upward force due to air resistance (terminal velocity). This terminal velocity depends on the objects drag coefficient, what the parachute does is present a drag coefficient sufficient to give the required terminal velocity for landing . > You need no more than say 6 metres / second landing velocity, effectively this is the terminal velocity with the chute open. Using body mass of 80 kg and acceleration due to gravity of 10 (m/s)/s, this gives a downward force of ( 80 * 10 ) 800 newtons. To balance this at landing velocity, you need a drag coefficient calculated from: 800 = velocity2 * drag coefficient , so: drag coefficient = 800 / velocity2 = 22.22 > Compare this to the pre chute deployment velocity of around 80 metres / second, giving a drag coefficient of: drag coefficient = 800 / 6400 = 0.125
How many f-15's does the air force have?
800
If two objects have a force of 800 pounds at some distance what will the force be if the distance is tripled?
Presuming we're talking about gravity here - since the force varies with the inverse square of distance, at triple the distance the force would be one ninth as strong or (800 / 9) pounds.
How can a person have an audition for acting on the internet?
If your acting career has gotten so pathetic that you need to resort to youtube, I recommend that you call the suicide hotline, and fast. 1 (800) 273 TALK
