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How is the neurotransmitter removed from a synaptic cleft?
Most neurotransmitters are removed by being taken up by the presynaptic or postsynaptic neurones however acetylcholine is the prime exeption to this as is actually destroyed in the synaptic cleft by the enzyme acetylcholinesterase. The reason this must happen is that otherwise the neurotransmitter would be left in the cleft where it would continue to evoke a response in the postsynaptic cell for longer than it should. For this reason reuptake and catabolic enzymes are often the targets of drugs gieven to treat neurological disorders. Another possible problem is wastage, if the neurotransmitter is left in the cleft it may difuse away and be wasted giving the presynaptic neurone more work to do creating more.
C program to reverse an array elements using dynamic memory allocation?
/* Write a C program to reverse the elements of a 1-D array using pointers. */ #include<stdio.h> #include<conio.h> #include<process.h> void REVERSE(int *ptr1, int *ptr2, int n); void main() { int X[30], m, i; clrscr(); printf("\n\n\n\tEnter the size of Array (Less than 30):"); scanf("%d",&m); if ((m > 30) (m < 2)) { printf("\n\n\t\tERROR !!!!!!"); printf("\n\t\tENTER SIZE WITHIN GIEVEN FIELDS....TRY AGAIN."); getch(); exit(0); } clrscr(); printf("\n\n\n\tEnter the elements of Array :"); for(i=0;i<m;i++) { printf("\nElement %d:",i+1); scanf("%d",&X[i]); } REVERSE(X,X,m); printf("\n\n\n\n\tThe Reversed Array is:\n"); for(i=0;i<m;i++) printf("\n\t\tElement %d: %d",i+1,X[i]); getch(); } void REVERSE(int *ptr1, int *ptr2, int n) { int *temp=NULL; int i; for(i=0;i<n;i++,ptr2++); for(i=0,ptr2--; i<(n/2); i++,ptr1++,ptr2--) { *temp=*ptr1; *ptr1=*ptr2; *ptr2=*temp; } } /************ PROGRAM ENDS ************/
