The amount of heat needed to melt 2 kg of ice is 334,000 Joules. This value is known as the heat of fusion of ice, which is 334 kJ/kg.
No, the amount of heat required to boil 1kg of water is much higher than the amount of heat required to melt 1kg of ice. Boiling water requires additional heat to overcome the latent heat of vaporization, while melting ice only requires heat to overcome the latent heat of fusion.
To calculate the heat needed to melt a block of ice at its melting point, you need to know the mass of the ice block, the specific heat capacity of ice, and the heat of fusion of ice (or latent heat of fusion). The formula to calculate this heat is Q = m * ΔHf, where Q is the heat energy, m is the mass, and ΔHf is the heat of fusion.
The heat required to melt ice at its melting point is known as the heat of fusion, which is 334 J/g. Therefore, the heat needed to melt 68.5 g of ice is 68.5 g x 334 J/g = 22,939 J.
To calculate the number of photons needed to melt the ice, you would need to determine the energy required to melt the ice and then convert that energy into photons at 660 nm. This involves calculating the energy required to melt the ice using the heat of fusion of ice and then dividing that by the energy of a photon at 660 nm.
In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state. The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice. 1 kg = 1000g 40kg x (1000g/1kg) = 40,000g Joules needed to melt the ice = 333.55 J/g x 40000 g = 13342000 J or 1.3342 x 107 J
The two amounts are the same but have the opposite sign (positive vs negative).
No, the amount of heat required to boil 1kg of water is much higher than the amount of heat required to melt 1kg of ice. Boiling water requires additional heat to overcome the latent heat of vaporization, while melting ice only requires heat to overcome the latent heat of fusion.
To calculate the heat needed to melt a block of ice at its melting point, you need to know the mass of the ice block, the specific heat capacity of ice, and the heat of fusion of ice (or latent heat of fusion). The formula to calculate this heat is Q = m * ΔHf, where Q is the heat energy, m is the mass, and ΔHf is the heat of fusion.
The specific latent heat/ latent heat of fusion of ice is 333.55 J/gtherefore by using the equation E=mLE = 54 * 333.55= 18011.7 JTherefore the energy needed to melt 54 grams of ice at its melting point which is keeping it at 0 degrees Celsius is 18011.7 Joules.
The heat required to melt ice at its melting point is known as the heat of fusion, which is 334 J/g. Therefore, the heat needed to melt 68.5 g of ice is 68.5 g x 334 J/g = 22,939 J.
When melting ice, you are moving from a solid to a liquid. Any state change from a solid to a liquid is called the heat of fusion. In other words, whenever melting takes place, the amount of energy needed is referred to as the heat of fusion.
The heat of fusion of water, which is the amount of heat energy required to melt one gram of ice at its melting point, is approximately 334 joules per gram. This means that to melt an ice cube, the ice must absorb 334 joules of heat energy per gram to transition from a solid to a liquid state.
Cold water will not melt the ice cube in record time, but hot water will, but salt water will also melt it fast, but if you add both together the ice cube will melt alot fast. Deceasing time alot.
To calculate this, we can use the formula: energy needed = mass * heat of fusion. The heat of fusion for ice is 334 J/g. Thus, the energy needed to melt 5 grams of ice is 5 grams * 334 J/g = 1670 Joules.
To melt ice at 0°C, 333 J/g of heat is needed. Therefore, to melt 65.77 g of ice, you would need 65.77 g * 333 J/g = 21914.41 J or 21.91 kJ of heat.
The heat needed to melt one gram of a solid at its melting point depends on the heat of fusion value of the solid. To melt one gram of ice, for example, would require 334 J.
To calculate the number of photons needed to melt the ice, you would need to determine the energy required to melt the ice and then convert that energy into photons at 660 nm. This involves calculating the energy required to melt the ice using the heat of fusion of ice and then dividing that by the energy of a photon at 660 nm.