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What is the average acceleration of a subway train that speeds up from 9.6 ms to 12 ms in 0.8 seconds on a straight section of track?
Wiki User
∙ 6y ago
3 m/s/s or 3 m/s^2
a = (vf-fi)/(delta t), where a = acceleration, vf = final velocity, vi = initial velocity, and delta t = time interval. vf = 12 m/s, vi = 9.6 m/s, and delta t = 0.8 s
Plug the known values into the equation and solve for acceleration.
a=(12 m/s - 9.6 m/s)/(0.8 s) = 3 m/s/s or 3 m/s^2
Wiki User
∙ 6y ago
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