The car's acceleration between 25s and 30s can be calculated by determining the change in velocity during that time interval and dividing it by the time elapsed. Acceleration = (final velocity - initial velocity) / time. You need to know the initial and final velocities of the car during that time period to calculate its acceleration.
v = u + at a = (v - u) / t u = 0 , v = 18 ms-1 , t = 30 s a = 18 / 30 = 0.6 ms-2
Well, honey, without knowing the force acting on that mass, you can't calculate acceleration. It's like trying to bake a cake with just flour and no recipe - you're missing a crucial ingredient. So, unless you have the force thrown into the mix, you're out of luck in finding that acceleration.
First find the acceleration rate (actually deceleration in this case). Equation is a = (v2- u2)/2s where a = acceleration, v = final velocity, u = initial velocity, s = distance but remember you must use consistent units, 60 km/hour = 16.67 meters/sec so v = 0, u = 16.67 so a = -16.672/2 x 30 = - 4.63 meters/sec2 , time = (v - u)/a = 16.67/4.63 = 3.60 secs.
To calculate the number of electrons passing through a conductor, we first convert the current to coulombs per second (C/s) by multiplying 4mA by 10^-3 to get 0.004A. Then multiply this by the total seconds in 1 min and 30s (90s) to get 0.36 coulombs. Since 1 electron has a charge of 1.6 x 10^-19 coulombs, divide the total charge by the charge of one electron to find the number of electrons passing through the conductor (0.36 / 1.6 x 10^-19 ≈ 2.25 x 10^18 electrons).
Wavelength = (speed) divided by (frequency)Speed = 425/10 = 42.5 cm/secFrequency = 40/30 = 4/3 Hz.Wavelength = 42.5 / (4/3) = 42.5 x (2/3) = [28 and 1/3] cm.
well landmarks in math are main #'s. like 5s, 10s, 15s, 20s, 25s, 30s, 35s, 40s, 45s, 50s, 55s, 60s, and so on and so on forever and ever.
the answer is 0
In the 30s hardware & appliance stores sold the Crosley. In the late 40s some Packard dealers sold the car but it was mainly sold as it was in the 30s. The Crosley was manufactured from 1939-1952
a = vf - vi/Δt, where a is acceleration, vf is final velocity, vi is initial velocity, and Δt is time interval. a = (7m/s - 1m/s)/30s = 6m/s/30s = 0.2m/s/s or 0.2m/s2
A girl will start dating between 18-30s
A trigenarian is a person who is in their thirties, typically between the ages of 30 and 39.
"Early 30s" typically refers to someone who is between 30 and 33 years old. This age range is generally considered to encompass the early part of the third decade of someone's life.
30s
A fullback typically wears a number between 1 to 49 MOST fullbacks wear a number in the 30s or 40s
A fullback typically wears a number between 1 to 49 MOST fullbacks wear a number in the 30s or 40s
20s and 30s are sizes of rims (in inches).
Diane was popular between the 30s up until the 60s http://www.thinkbabynames.com/meaning/0/Diane