The acceleration of the car is calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the given values, the acceleration of the car is (20 m/s - 5 m/s) / 3 s = 5 m/s^2.
The answer will be 5 m/sec/sec 300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
The acceleration of the car can be calculated using the formula ( \text{acceleration} = \frac{\text{change in velocity}}{\text{time taken}} ). In this case, the change in velocity is 20 m/s - 5 m/s = 15 m/s, and the time taken is 3 s. Therefore, the acceleration of the car is ( \frac{15 \text{ m/s}}{3 \text{ s}} = 5 \text{ m/s}^2 ).
The acceleration of the object is 20 m/s^2. This is because acceleration is defined as the change in velocity per unit time, and in this case the object's speed is increasing by 20 m/s every second of fall.
The car's uniform acceleration is (change in speed) divided by (change in time) = (24 m/s) / (2.95 s) = 8.1356 meters/sec2. Call this number ' A ' for acceleration. Change in speed = ( A ) times (time) Time = (change in speed) / A = (20 - 10) / A = 10/A = 0.81356 seconds (rounded)
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 20+10 = 30 miles/sec, the initial velocity is 20 miles/sec, and the time is 30 seconds. So, the acceleration of the car is (30 - 20) / 30 = 0.33 miles/sec^2.
Acceleration = change in speed/time = (20-5)/3 = 15/3 = 5 units of speed per second. It is not possible to be any more precise because the unit of speed (kilometres per hour, miles per hour, metres per second) is unspecified.
Acceleration = Change in speed/Time Time = Change in Speed/Acceleration = 65mph/20mph per s = 65/20 seconds = 3.25 seconds
The answer will be 5 m/sec/sec 300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
3 ms-2
The formula for finding time based on acceleration and speed is: (Delta)t = (Delta)v/a Change in time = change in speed / acceleration t = 75-15 / 20 t = 60 / 20 t = 3 seconds
-- "Acceleration" is any change of velocity.-- "Velocity" is a speed and its direction.-- "20 meters per second" is a speed, not a velocity, because it doesn't mention a direction.-- We don't have enough information to say anything about that car's acceleration.If, for example, it happens to be moving at a constant speed of 20 meters per secondon a circular track, then it has plenty of acceleration.
20 MPH would be colder, as the increased speed increased heat transfer away from the moving object.
5 m/s2 east
well we know that we have two speeds and a time. So, initial speed = 80 final speed = 60 change in time = 6 Now acceleration in this case will be measured in kilometers per hour per second (i.e. every x seconds, y kilometers per hour are gained in speed) So we simply apply the formula Acceleration = (final speed - initial speed)/ change in time = (80 - 60)/6 = 20/6 = 3.6666667 km/h/s
The acceleration of the car can be calculated using the formula ( \text{acceleration} = \frac{\text{change in velocity}}{\text{time taken}} ). In this case, the change in velocity is 20 m/s - 5 m/s = 15 m/s, and the time taken is 3 s. Therefore, the acceleration of the car is ( \frac{15 \text{ m/s}}{3 \text{ s}} = 5 \text{ m/s}^2 ).
A car is a motor vehicle with wheels, used for transportation. Acceleration is the rate at which an object changes its velocity. In this case, the car increases its speed from 5 m/s to 20 m/s over 3 seconds, resulting in an acceleration of (20 m/s - 5 m/s) / 3 s = 5 m/s².
The acceleration of the object is 20 m/s^2. This is because acceleration is defined as the change in velocity per unit time, and in this case the object's speed is increasing by 20 m/s every second of fall.