The clock period is the time duration of one clock cycle. For a clock frequency of 1 GHz (1 billion hertz), the clock period would be 1 nanosecond (1/1,000,000,000 seconds).
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
The frequency of a clock's waveform with a period of 35 microseconds can be calculated by taking the reciprocal of the period. Thus, the frequency would be 1 / 35 microseconds, which is approximately 28.57 kHz.
The period of a timer is the reciprocal of its frequency, meaning that period (T) = 1/frequency (f). As the frequency of a timer increases, its period decreases inversely (and vice versa). For example, a timer with a frequency of 1 Hz (1 cycle per second) will have a period of 1 second, while a timer with a frequency of 10 Hz will have a period of 0.1 seconds.
increase. The frequency of a wave is inversely proportional to its period, meaning that as the period decreases, the frequency increases. The relationship between frequency and period is given by the formula: frequency = 1 / period.
A period can't be 4 Hz; those are the wrong units. If the period is 1/(4Hz), then the frequency is 4Hz. If the period is 4 seconds, then the frequency is 0.25 Hz. They are inversely related.
The clock period of a microprocessor is the inverse of its clock frequency. For a clock frequency of 100 MHz, the clock period can be calculated as follows: Clock Period = 1 / Frequency = 1 / 100,000,000 seconds = 10 nanoseconds. Therefore, the clock period is 10 nanoseconds.
If you have the Maximum clock frequency, then you can figure out the minimum clock period using this formula: 1/(minimum clock period) = (Maximum clock frequency).
The clock period is calculated as the inverse of the clock frequency. It can be determined using the formula: [ \text{Clock Period} (T) = \frac{1}{\text{Clock Frequency} (f)} ] For example, if the clock frequency is 2 GHz, the clock period would be ( T = \frac{1}{2 \times 10^9} = 0.5 ) nanoseconds.
The period of 1GHz is 1 ns. The waveform is irrelevant.
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
The clock out frequency of an 8085 is one half the crystal frequency. The period of one T cycle is the inverse of the clock frequency. At a crystal frequency of 5MHz, the clock is 2.5MHz, and T is 400 ns.
A clock with a period of 1 ns has a frequency of 1 GHz, or 1000 MHz.
The frequency of a clock's waveform with a period of 35 microseconds can be calculated by taking the reciprocal of the period. Thus, the frequency would be 1 / 35 microseconds, which is approximately 28.57 kHz.
The Ku band of microwave frequencies ranges from 12 to 18 GHz. A frequency of 1GHz is not in the Ku band. There is no correspondence. Is the 1GHz setting on the spectrum analyzer a center frequency? Or is it one of the ends of the spectrum analyzed? Is it the width of the spectrum being analyzed? And if it is the latter, what is its center? Knowing these things will still not change the answer given, but may help to "sort out" a possible problem with the question the way it is written.
SNAPDRAGON Mobile Processor
Period = 1 / frequency
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