It is named as buoyant force which always acts in the upward direction ie opposite to the weight of the body. So actual weight appears to be reduced. Hence apparent weight loss
When weight of an object is equal to upthrust then object will float and when weight of an object is greater than upthrust ,the object will sink.
It tends to float the submerged object on the surface of that medium.
Water pressure is greatest against the bottom of a submerged object?
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
Forces are exerted on a submerged object due to water pressure not being balanced due to buoyancy. This is when the pressure at the bottom of the submerged object is greater than the fluid on the top of the object, thus projecting the object upward.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
It tends to float the submerged object on the surface of that medium.
Water pressure is greatest against the bottom of a submerged object?
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
Forces are exerted on a submerged object due to water pressure not being balanced due to buoyancy. This is when the pressure at the bottom of the submerged object is greater than the fluid on the top of the object, thus projecting the object upward.
The buoyant force on a fully submerged object is equal to the weight of the water displaced. In fact, that's also true of a floating object.
The greater the pressure against the bottom of a submerged object produces an upward buoyant force
Any submerged object that have less dense than the water it will float. Therefore your submerged object probably will float because it has less dense than the water. I hope my answer helped you.=)
A submerged object will displace its own volume of the liquid it is submerged in.
They are equal.
They are equal.