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1s2 2s2 2p6 3s2 3p6 4s2 3d3 For abbreviation: [Ca] 3d3

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14y ago
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11y ago

Vanadium, V, atomnumber 23 has the following electron configuration:

1s2, 2s2 2p6, 3s2 3p6, 4s2, 3d3

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13y ago

It is not [Ar] 4s2

In V 3+ the element Vanadium is giving away 3 of its electrons. 50.9 - 3 is 47.9, about the same as Titanium (Ti). So the answer would be [Ar] 4s^0 3d^2

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11y ago

In3+ ion:

[Kr] 4d10

or

2, 8, 18, 18

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13y ago

[Ar] or 1s2 2s2 2p6 3s2 3p6

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Q: What is the electron configuration of of In3 plus ion?
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