The photon energy of 1022 Hz is 4.22664452E-12 electron volts.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the photon. Plugging in the values, the energy of a photon of red light with a frequency of 4.48 x 10^14 Hz is approximately 2.98 x 10^-19 Joules.
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz is approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J s) and f is the frequency of the photon. So, for a photon with a frequency of 6 x 10^12 Hz, the energy would be approximately 3.98 x 10^-21 Joules.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
The frequecy is o,74958 Hz.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
To arrange photons in order of increasing energy, you can use the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. Photons with higher frequency will have higher energy. So, simply compare the frequencies of the photons to determine their energy order.
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the photon. Plugging in the values, the energy of a photon of red light with a frequency of 4.48 x 10^14 Hz is approximately 2.98 x 10^-19 Joules.
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz is approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J s) and f is the frequency of the photon. So, for a photon with a frequency of 6 x 10^12 Hz, the energy would be approximately 3.98 x 10^-21 Joules.
If the change in energy of electron is totally exhibited as a photon then the energy = h times frequency. h = 6.626 x 10 to -34 J s Simply multiply h and frequency you would get the energy in joule
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. Substituting the given frequency of 7.211014 Hz into the equation, we find that the energy of the photon is approximately 4.79 x 10^-33 J.
The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 4 x 10^7 Hz is approximately 2.65 x 10^-26 Joules.
The energy of a photon can be calculated using the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz would be approximately 3.98 x 10^-21 Joules.
5.10 x 10^14 hz