The energy of a photon with a frequency of 7.5 x 10^14 Hz can be calculated using the formula E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 Js), and f is the frequency. Plugging in the values, we get E = (6.626 x 10^-34 Js)(7.5 x 10^14 Hz) ≈ 4.97 x 10^-19 J.
2.96 x 10^-19 J
The wavelength is 671 nm.
The energy of a quantum of light is given by the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Substituting the values, the energy of a quantum of light with a frequency of 7.39 x 10^14 Hz would be approximately 4.90 x 10^-19 Joules.
The energy of a photon can be calculated using the formula E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J.s), and f is the frequency of the light. Plugging in the values, the energy of a photon emitting a light frequency of 7.21 x 10^14 Hz is approximately 4.85 x 10^-19 J.
The energy of a wave is proportional to its frequency. The energy of a wave with a frequency of 2400 Hz depends on factors such as the amplitude, medium through which the wave is traveling, and wave equation.
4.25 10-19 j
2.96 x 10^-19 J
The frequency of red light is 4×1014 Hz. (Wikipedia)
2.96 x 10-19 J
5.69 × 1014 Hz
6.52 1014 Hz
Frequencies: .003 - 4 x 1014 Hz
1014 Hz
The wavelength is 671 nm.
The energy of a quantum of light is given by the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Substituting the values, the energy of a quantum of light with a frequency of 7.39 x 10^14 Hz would be approximately 4.90 x 10^-19 Joules.
It ranges from 4.28 x 1014 Hz for red light to 7.89 x 1014 Hz for violet light.
To arrange photons in order of increasing energy, you can use the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. Photons with higher frequency will have higher energy. So, simply compare the frequencies of the photons to determine their energy order.