The enthalpy of dry air at 700 kPa is ~1016 J/kg(degreeC)
so at 450K the temperature is 177 C
this would make the Enthalpy of dry air ~ 179.832 kJ/kg at 177 C
450 kPa is equivalent to approximately 65.3 psi (pounds per square inch).
The average air pressure at sea level is around 101.3 kilopascals (kPa).
783,0 mm Hg is equal to 104,3914 kPa.
6.9 kPa = 1 psi
Yes. 85 psi is equal to about 586.1 kPa
550 to 700 kpa
Celsius plus pie squared and add your decimal with your demoninator with the odd and even number then find out the sum
kpa and pa....kpa= kilopascals and pa= pascals
To convert inches of water to kilopascals (kPa), multiply the value by 0.2488. Therefore, to convert 0 to 7 inches of water air flow to kPa, multiply each value by 0.2488 to get the equivalent air flow in kPa.
450 kPa is equivalent to approximately 65.3 psi (pounds per square inch).
Using Boyle's Law (P1V1 = P2V2), we can find the new volume by rearranging the formula to V2 = (P1 * V1) / P2. Plugging in the values, we get V2 = (200 kPa * 10 m^3) / 800 kPa = 2.5 m^3. Therefore, the new volume of air will be 2.5 m^3.
One liter of air at 101.325 equals on liter of air at 101.325. It is a trick question of sorts, because the metric unit of measurement "liter" is defined by said amount of matter in an atmosphere of 101.325 KPa.
The average air pressure at sea level is around 101.3 kilopascals (kPa).
Troposphere: 101.3 kPa Stratosphere: 30.0 kPa Mesosphere: 0.3 kPa Thermosphere: 0.001 kPa
13.78 kpa is.
Conversion for kPa to mmHG: kPa x 7.501 = mmHg202.6 kPa x 7.501 = about 1,520 mmHg
783,0 mm Hg is equal to 104,3914 kPa.