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What is the equation for beta decay of uranium-237?
The beta decay of uranium-237 can be represented by the equation: (^{237}{92}U \to ^{237}{93}Np + e^- + \bar{\nu_e}) where (^{237}{92}U) decays into (^{237}{93}Np), an electron (e^-), and an electron antineutrino (\bar{\nu_e}).
Neptunium's only naturally occurring isotope 237 93Np decays by emitting one alpha particle one beta particle and one gamma ray What is the new atom formed from this decay?
The new atom formed from the decay of Neptunium-237 is Protactinium-233. After emitting an alpha particle (Helium-4 nucleus), a beta particle (electron or positron), and a gamma ray (photon), Neptunium-237 transmutes into Protactinium-233.
How many ounces is 237 ml?
187mL equates to 6.32 US fluid ounces.
What radioactive element is used in nuclear fuel?
The most commonly used radioactive fuel is Plutonium (Pu) 238, which is alpha active and produces a useful amount of thermal energy, without the need for much shielding. This material is produced from Neptunium 237, which is separated out from spent reactor fuel. The Pu238 is assembled with a thermocouple array to produce a small amount of electricity, and is widely used in satellites if solar panels are not viable. Pu 238 has a half life of 87 years, so can power applications where the mission lasts a long duration. Other materials have been used, amongst them Strontium 90, but Pu238 is now the favourite. Wikipedia has entries giving more information-see 'Nuclear Fuel' section 8
How many ounces in 237 grams?
1 ounce equals 28 grams. So 237 G. / 28 = 8.464 or 8-1/2 Ounces rounded up!
What is the equation for beta decay of uranium-237?
The beta decay of uranium-237 can be represented by the equation: (^{237}{92}U \to ^{237}{93}Np + e^- + \bar{\nu_e}) where (^{237}{92}U) decays into (^{237}{93}Np), an electron (e^-), and an electron antineutrino (\bar{\nu_e}).
What is the equation of decay for americium 241?
Emitting alpha particles Am-241 decay to Np-237.
What type of decay does Am-241 undergo to become Np-237?
Americium-241 undergoes alpha decay to become Neptunium-237. During alpha decay, an alpha particle (two protons and two neutrons) is emitted, resulting in the conversion of Americium-241 to Neptunium-237.
What is the decay products of americium 241?
The decay products of americium-241 include neptunium-237, plutonium-241, and various isotopes of neptunium, plutonium, and uranium. These decay products are formed as americium-241 undergoes alpha decay and transforms into new elements through a series of radioactive decays.
Which daughter element is produced from the alpha decay of americium 241?
The alpha decay of americium-241 produce neptunium-237.
What is the equation for uranium decay?
Uranium-237 will undergo beta minus decay to neptunium-237 according to the following equation: 92U237 => 93Np237 + e- + 0.519 MeV At the risk of being a bore, a neutron in U237 undergoes a weak interaction-mediated change into a proton and an electron. The electron will be ejected from the nucleus immediately. Along with the electron, which leaves with a lot of kinetic energy, we'll see an antineutrino and the decay energy (0.519 MeV).
What type od decay does Am-241undergo to become Np-237?
alpha
What is the product of alpha decay for americium -241?
The intermediate product is neptunium 237 ( a very long-lived radioisotope).
How many neutrons are there in uranium - 237?
Uranium-237 has 142 neutrons. This can be determined by subtracting the atomic number (92) from the atomic mass (237) of uranium-237.
When one neptunium isotope undergoes an alpha decay what does it become?
Npn decays to Pan-4 and alpha. Only isotopes 234, 235, and 237 of neptunium can undergo alpha decay, the others decay by beta-, beta+, K capture, and/or gamma decay. So the only products of neptunium alpha decay can be protactinium isotopes 230, 231, or 233.
What would Americium transmute into if it expelled an alpha particle?
For example americium-241 decay to neptunium-237 and americium-243 decay to neptunium-239.
What is the equation for Plutonium-241 decay?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
