You now have enough information to calculate the wire volume. First convert the length to inches: 2 feet = 24 inches. Now use the appropriate equation: V = (πd2L)/4: Volume = (π • (0.081 in)2 • 24 inches) /4 = 0.124 cubic inches.
The equation for work in terms of pressure and volume is: Work Pressure x Change in Volume.
The partial derivative of the van der Waals equation with respect to volume is the derivative of the equation with respect to volume while keeping other variables constant.
If you increase the length of a wire while keeping the volume constant, the wire's thickness will decrease proportionally. This is because the volume of the wire is distributed over a longer length, resulting in a thinner wire.
The density of copper wire can be calculated by dividing its mass by its volume. In this case, the density of the copper wire is 6g / 9cm^3 = 0.67 g/cm^3.
The enthalpy of air can be calculated using the equation: enthalpy internal energy pressure volume. This equation takes into account the internal energy of the air and the pressure and volume of the system.
To work out the mass of wire you need to know its volume. The wire is circular so that volume would just be the cross sectional area (pi * r^2) multiplied by the length of wire. Lets call the length L. The equation is then volume = pi * radius^2 * L. To get the mass of the wire we now multiply this equation by denstiy of the wire; that is how much the wire weighs per volume. Assuming the wire is steel this would be around 800Kg/m^3. So what you want to do is work out the volume as above, then multiply by 800, making sure that your units are consistant....ie lenght and radius in metres.
Volume = 0.
The equation for work in terms of pressure and volume is: Work Pressure x Change in Volume.
Use the equation for the volume of a cone, replace the known height and volume, and solve the resulting equation for the radius.
ring volume formula ring volume formula
ring volume formula ring volume formula
The partial derivative of the van der Waals equation with respect to volume is the derivative of the equation with respect to volume while keeping other variables constant.
If you increase the length of a wire while keeping the volume constant, the wire's thickness will decrease proportionally. This is because the volume of the wire is distributed over a longer length, resulting in a thinner wire.
Since a triangle is two-dimensional, it cannot have volume.
There is no such equation, what do you mean by "water from a distance".
Volume = area of pentagon x length of prism.
Width x Length x Height = Volume.