235 235 0
Th= Pa + e
90 91 -1
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
The decay product of uranium 238 by alpha disintegration (not beta or gamma) is thorium 234.
alpha particles.
If a uranium-244 atom undergoes alpha decay, it will become an atom of thorium-240. If we wrote an equation, it might look like this:92244U => 90240Th + 24He++The uranium-244 is transmuted into throium-240, and the alpha particle, which is a helium-4 nucleus (and represented as such) emerges at the tail end of the equation.
Alpha emission means a He (A=4, Z=2) core is released along with energy. Helium's atomic number is 2 and the atomic mass is 4. So when Thorium (A=x, Z=90) emits an alpha particle it becomes a Radium (A=x-4, Z=88). By the way: Thorium is very vague when it comes to nuclear physics. It's important to state the atomic mass of the atom. There exist many forms of each element, called isotopes.
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
Thorium-234 don't emit alpha particles.
What is missing is the type of decay that occurs during the transformation. For example, uranium-238 decays into thorium-234 through alpha decay, so the missing component would be the emission of an alpha particle in the balanced equation.
When uranium radiates alpha particles, it transforms into thorium. Thorium is a radioactive element that is produced as a result of the decay of uranium through alpha emission.
Uranium 238 is transformed in thorium 234 by alpha decay.
When uranium undergoes alpha decay, it emits an alpha particle (which consists of 2 protons and 2 neutrons) and transforms into thorium. The mass of the thorium produced can be determined by subtracting the mass of the emitted alpha particle from the original mass of the uranium nuclide. The specific mass of thorium will depend on the isotope of uranium that is decaying, but it generally corresponds to the mass number of the uranium minus 4 (for the alpha particle).
The decay product of uranium 238 by alpha disintegration (not beta or gamma) is thorium 234.
alpha particles.
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
When uranium undergoes alpha decay, it emits an alpha particle (which is equivalent to a helium nucleus, ( ^4_2He )), resulting in a decrease of its atomic number by 2 and its mass number by 4. For example, if uranium-238 (( ^{238}{92}U )) undergoes alpha decay, it transforms into thorium-234 (( ^{234}{90}Th )). Thus, the notation for the thorium isotope produced is ( ^{234}_{90}Th ).
If a uranium-244 atom undergoes alpha decay, it will become an atom of thorium-240. If we wrote an equation, it might look like this:92244U => 90240Th + 24He++The uranium-244 is transmuted into throium-240, and the alpha particle, which is a helium-4 nucleus (and represented as such) emerges at the tail end of the equation.
It is 90.