down and up forces balance at terminal velocity
mass * g = v^2 * drag coefficient
if mass and terminal velocity are known , drag coefficient can be found
say mass = 100 kg, g = 9.8 (m/s)/s, terminal velocity = 70 m/s
so at terminal velocity:
100*9.8=4900* drag coefficient
then:
100*9.8/4900 = 0.2 (drag coefficient)
if you reduce the drag coefficient, the terminal velocity will increase, until the forces balance
If resistance is negligible, then there is no terminal velocity.
Without air resistance, there would be no such thing as terminal velocity.
That is called terminal velocity.That is called terminal velocity.That is called terminal velocity.That is called terminal velocity.
Air resistance increases and terminal velocity decreases when the parachute has opened.
That is the object's terminal velocity.
If resistance is negligible, then there is no terminal velocity.
Without air resistance, there would be no such thing as terminal velocity.
terminal velocity
That is called terminal velocity.That is called terminal velocity.That is called terminal velocity.That is called terminal velocity.
Air resistance increases and terminal velocity decreases when the parachute has opened.
No. Terminal velocity is a particular kind of velocity and friction is a particular kind of force. The terminal velocity of a falling object is the maximum velocity it can have because air resistance prevents it from going any faster. And air resistance is a type of friction. So terminal velocity is due to a type of friction.
When terminal velocity is reached, the gravitational force is balanced with the force of resistance.
More resistance, caused by a greater density.
That is the object's terminal velocity.
because there is more air resistance
In that case, the object is said to have achieved terminal speed.
Its the air resistance that causes the free falling body to reach its terminal velocity