For equilibrium, the sum of all torques must be zero.
An object is in rotational equilibrium when the net torque acting on it is zero. This occurs when the clockwise torques are balanced by counterclockwise torques, resulting in no rotational acceleration.
No, for an object to be in equilibrium, the net torque acting on it must be zero. If all torques are producing clockwise rotation, there will be a net torque causing the object to rotate in that direction, not in equilibrium.
In a condition of equilibrium, the sum of all torques acting on an object must be zero because torque is responsible for rotation. If the total torque is not balanced (i.e., not zero), the object will start rotating. By ensuring that the sum of all torques is zero, we guarantee that the object stays in a stable, balanced position without any rotational movement.
In equilibrium, the net force acting on the body is zero, meaning that the body is either at rest or moving at a constant velocity. Additionally, the sum of all torques acting on the body is zero, indicating rotational equilibrium.
For complete equilibrium of a body, the sum of all forces acting on the body must be zero (ΣF = 0) and the sum of all torques acting on the body about any point must also be zero (Στ = 0). This means that both the translational and rotational aspects of equilibrium are satisfied, ensuring that the body remains stationary and does not rotate.
An object is in rotational equilibrium when the net torque acting on it is zero. This occurs when the clockwise torques are balanced by counterclockwise torques, resulting in no rotational acceleration.
No, for an object to be in equilibrium, the net torque acting on it must be zero. If all torques are producing clockwise rotation, there will be a net torque causing the object to rotate in that direction, not in equilibrium.
when vector sum of all forces and all torques is zero.
In a condition of equilibrium, the sum of all torques acting on an object must be zero because torque is responsible for rotation. If the total torque is not balanced (i.e., not zero), the object will start rotating. By ensuring that the sum of all torques is zero, we guarantee that the object stays in a stable, balanced position without any rotational movement.
Coplanar or not, the two conditions for equilibrium are:The sum of all forces must be zeroThe sum of all torques must be zero.
No. For equilibrium, the SUM OF ALL FORCES acting on an object must be zero, and that is not possible with a single (non-zero) force.Note: For equilibrium, the sum of all torques on an object must ALSO be zero.
In equilibrium, the net force acting on the body is zero, meaning that the body is either at rest or moving at a constant velocity. Additionally, the sum of all torques acting on the body is zero, indicating rotational equilibrium.
I am not sure about numbering, but for an object to be in equilibrium, two conditions must be fulfilled:The sum of all the forces on the object must be zero.The sum of all the torques must be zero.
For complete equilibrium of a body, the sum of all forces acting on the body must be zero (ΣF = 0) and the sum of all torques acting on the body about any point must also be zero (Στ = 0). This means that both the translational and rotational aspects of equilibrium are satisfied, ensuring that the body remains stationary and does not rotate.
No. There are two conditions for equilibrium; both must be met:1) The sum of all forces must be zero.2) The sum of all torques must be zero.
In a system in equilibrium, the sum of all forces acting on an object must be zero according to Newton's first law of motion. Additionally, for a system in rotational equilibrium, the sum of all torques must also be zero.
Anticlockwise equilibrium refers to a state where the net torque acting on an object causes it to rotate counterclockwise, while clockwise equilibrium refers to a state where the net torque causes the object to rotate clockwise. In both cases, the object is in rotational equilibrium because the torques are balanced and there is no angular acceleration.