The fifth harmonic of a 500 Hz triangular wave would be at a frequency of 2500 Hz. This means that the fifth harmonic would have a frequency that is five times the fundamental frequency of the triangular wave.
Use the universal wave equation,v=fxlambdawhere v is velocity/speedf is frequencyand lambda is wavelengthv=(500)(0.5)= 250 m/s
Period = reciprocal of frequency = 1 / (500) = 0.002 second
AnswerSpeed of a wave = Wavelength x frequencyv = 0.5 x 500v = 250 m/sAnswerIf it is an electromagnetic wave, then the speed is that of light - 'c (in vacuum)'.
The frequency of a sound wave can be calculated using the formula: frequency = speed of sound / wavelength. Plugging in the values given, the frequency would be approximately 500 Hz.
The frequency of a wave can be calculated using the formula: frequency = speed of light / wavelength. Given that the speed of light is approximately 3 x 10^8 meters per second and the wavelength is 500 nanometers (which is 500 x 10^-9 meters), the frequency would be approximately 6 x 10^14 hertz.
2500 hz
2/5 of 500 is 200.
one fifth as long as 500
100 meters.
2500 / 5 is equal to 500
Use the universal wave equation,v=fxlambdawhere v is velocity/speedf is frequencyand lambda is wavelengthv=(500)(0.5)= 250 m/s
The fifth century A.D (or C.E.) is from the years 401 to 500 on the Gregorian calandar.
The second harmonic will be 2 x the fundamental; the third harmonic is 3 x the fundamental: 500 Hz, and 750Hz.
500
Fifth century encompasses the years 401-500.
500 W power
a Lateen Sail