What is the force of gravity between two 1050kg cars separated by a distance of 31m on an interstate highway?

Answer 1

Assume the centers of mass of the cars are 25m apart :

F = G m1m2 / R2

G = 6.673 x 10-11

F = (6.673 x 10-11) (1,000)(1,000)/(25)2 = 0.0000001068 newton (rounded)

(about 0.000000384 ounce)

Answer 2

F = G M1M2/R2

G = 6.673 x 10-11 m3/kg-sec2

M1 = 1,050 kg

M2 = 1,050 kg

R = 31 m

F = (6.673 x 10-11) x (1, 050) x (1,050)/(31)2 = 7.655 x 10-8 newton = about 0.000000276 ounce

Answer 3

The force of gravity between two 1050kg cars on an interstate highway would be incredibly small and negligible compared to other forces at play, such as the force of friction or air resistance. The force of gravity between the two cars can be calculated using Newton's law of universal gravitation, but the resulting value would be extremely tiny and practically insignificant in the context of their interaction on the highway.

Answer 4

The force is 1.69*10^-7 Newtons = 169 nano newtons.