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What is the force of gravity between two 74kg physics students that are sitting 85cm apart?
F = G M1 M2 / D2
G = 6.673 x 10-11 M3 Kg-1 Sec-2
M1 = M2 = 74 kg
D = 0.85
F = (6.673 x 10-11) x 74 x 74 / (0.85)2 = 0.000 000 505 76 newton
(about 0.000 001 82 ounce of force)
This calculation assumes that their centers of mass are 85cm apart, which
is quite cozy. If instead it's their elbows that are 85cm apart, then the force
between them is considerably less.
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