Take the sum of the forces on the object on the horizontal plane(x-direction) with the positive direction being to the right. The 80 newtons to the right is +80N and the 80 newtons acting to the left is -80N. Add them up, so 80N - 80N = 0 N. The total force acting on the object is 0.
The net force is the difference between the two forces. So, the net force would be 40N - 30N = 10N to the right.
The net force acting on the object is 6 newtons to the left. This is calculated by subtracting the force pulling to the right (3N) from the force pulling to the left (9N).
The net force is 34 newtons directed to the right.
The net force is 4 N to the right (9 N - 5 N = 4 N).
The direction of the force is to the right. To calculate the magnitude of the force, you can use the formula: Force = (mass x distance) / time. Here, the force is 10 Newtons, the distance is 4 meters, and the time is 9 seconds. Plugging these values into the formula, the magnitude of the force is about 4.44 Newtons.
An object at rest pulled in opposite directions by unequal forces will start to move in the direction of the net force. For example, if I have a chair, and I'm pushing with 10 newtons to the right, and my sister is pushing 5 newtons to the left, the net force is 5 newtons to the right. Therefore, I win, and the chair moves to the right, in the direction of the net force.
The net force is the difference between the two forces. So, the net force would be 40N - 30N = 10N to the right.
The net force acting on the object is 6 newtons to the left. This is calculated by subtracting the force pulling to the right (3N) from the force pulling to the left (9N).
The net force is 34 newtons directed to the right.
The net force is 4 N to the right (9 N - 5 N = 4 N).
The direction of the force is to the right. To calculate the magnitude of the force, you can use the formula: Force = (mass x distance) / time. Here, the force is 10 Newtons, the distance is 4 meters, and the time is 9 seconds. Plugging these values into the formula, the magnitude of the force is about 4.44 Newtons.
The net force on the cart would be 0 Newtons because the forces pulling to the right and left are equal in magnitude but opposite in direction, resulting in a balanced force situation.
The net force is 5 newtons to the left (7 N - 2 N = 5 N).
Consider an object in empty space. There are two forces pushing from opposite sides, one force (force A) on the left pushing with 2 newtons of force, the other (force B) on the right pushing with 1 newton. Since force A is pushing with a greater force than force B, the result will be the object moving right. The object is also moving with a force of 1 newton, because force A is 1 newton greater than force B.
Please someone answer!!!!!
In this case you can simply subtract the two forces.
It's easiest to think about net force in a one dimensional world (a line). Say force 1 is exerting two newtons on the left side of object A (pushing it to the right), and force 2 is exerting 4 newtons on the opposite side of object A. All you have to do is subtract the two forces and you end up with 2 newtons being exerted on the right side of object A, accelerating it to the left. On a plane or in space, it's the same concept. What I find easiest to do, especially for plains, is to plot the forces, using the object as the origin. Then I draw each force vector, but instead of having them all extend off the object, I draw them off one another, e.g. the start of one vector is the end of the previous one. I then calculate the distance between the endpoint of all the vectors and the objects, and that is the net force.