Time interval is relative to tf - ti. "tf" stands for "final time" and "ti" stands for "initial time." It is used to find out how long it takes to get from one place to another. The full equation is "Δt = tf - ti" where delta (the triangle) represents the time interval. To make things clearer, let me use an example from my physics textbook.
Say it takes a runner one second to get to a tree, and he starts timing himself from there how long it will take him to get to a nearby lamppost. If, from the very beginning, it took him five seconds to get to the lamppost, and one second to get to the tree, it would take four seconds to get from the tree to the lamppost. The equation would look something like this: tf - ti = 5.0 s - 1.0 s = 4.0 s.
You need the amount of water, the temperature of the water, and the desired temperature.
Temperature is easy to convert from Fahrenheit to Celsius yourself. You can use the formula Tc = (5/9)*(Tf-32) where Tc = temperature in degrees Celsius, Tf = temperature in degrees Fahrenheit. 99.8 F is 38 C.
Temperature is easy to convert from Fahrenheit to Celsius yourself. You can use the formula Tc = (5/9)*(Tf-32) where Tc = temperature in degrees Celsius, Tf = temperature in degrees Fahrenheit. 100 F is 37.8C.
Short answer 5.0 s Long answer From the question the following information is known a = -9.8 m/s2 vi = 0 m/s vf = -49 m/s ti = 0 s using the formula a = Δv/Δt since initial velocity/time = 0 a = vf/tf solve for t (multiply both sides by t and divide both sides by a) tf = vf/a tf = (-49 m/s)/(-9.8 m/s2) = 5.0 s
Tf = ((9/5)*Tc) + 32 is the formula used for the required conversion.
Average Acceleration = V/t = Vf-Vi / Tf-Ti
q = C x m x (Tf-Ti), where q is heat, C is specific heat capacity, m is mass in grams, and (Tf-Ti) is change in temperature.
The sum of the heat flows from each quantity of water = zero. Or heat lost by Hot water = Heat gained by cold water; Heat lost by hot water is MC(Ti - Tf) Heat gained by cold water is; mC(Tf - ti) M = mass of hot water, m= mass of cold water, Ti = initial tenperature of hot water, ti = initial temperature of cold water, C = specific heat of water, Tf final temp of both waters. mC(Tf - ti) = MC(Ti -Tf)) Tf(m + M) = mti + MTi Tf = (mti + MTi)/(m + M)
Ti - were you hoping for something else ? ;-)
Time taken... to do what exactly? There are lots of formulae that involve time. You would have to be a bit more specific.
Use this formula. Tf = Tc(1.80) + 32
Formula: Ti
absorbed: endothermic released: exothermic however, substances rarely do this when changing state ()i.e solid to liquid etc() but it is common in chemical reactions ()Lithium+water for example()
You need the amount of water, the temperature of the water, and the desired temperature.
Final velocity vf is greater than the initial velocity vi . That is vf > vi . This is an example of acceleration (positive). Average acceleration aav = [vf - vi]/[tf - ti] where ti is initial time, and tf is final time.
The heat flow , Q, due to temperature is found by the formula; Q = mC(Tf - Ti) Where m is the mass of the substance (50g), C is the heat capacity of the substance (C for water is 1cal/g-deg), and Tf & Ti are the final and initial temperatures of the substance (37 & 100). If the answer comes out negative the substance lost heat. If it comes out positive it gained heat.
Ti