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The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is the Planck constant (6.626 x 10^-34 Js), and f is the frequency. Rearranging the formula to solve for f gives f = E/h. Plugging in the values, we find f ≈ (3.38 x 10^-19 J) / (6.626 x 10^-34 Js) ≈ 5.10 x 10^14 Hz.
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Find the energy of a photon whose frequency is 5x10 12 Hz?
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
What is the energy of a photon of 325nm?
The energy of a photon is determined by the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, calculate the frequency of the photon using the speed of light equation, c = λf. Then, substitute the frequency into the energy equation to find the energy of the photon.
What is the energy of photon?
the energy of a photon is h times f
What is the frequency of a photon with energy of 3.0 x 1013 eV?
The frequency of a photon can be calculated using the formula: E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Converting the energy to Joules gives E = 4.8 x 10^-19 J. Plugging in these values, we find that the frequency of the photon is approximately 7.36 x 10^22 Hz.
What is the frequency of a radar photon with energy 6.80x10 J?
The frequency of a photon is given by dividing its energy by Planck's constant (6.63 x 10^-34 J·s). So, for a photon with an energy of 6.80 x 10^-19 J, the frequency would be (6.80 x 10^19 J) / (6.63 x 10^-34 J·s) = approximately 1.03 x 10^14 Hz.
Find the energy of a photon whose frequency is 5x10 12 Hz?
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
What is the energy of a photon of 325nm?
The energy of a photon is determined by the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, calculate the frequency of the photon using the speed of light equation, c = λf. Then, substitute the frequency into the energy equation to find the energy of the photon.
What is the energy of photon?
the energy of a photon is h times f
If the photon has a frequency of 4 x 1015 Hz how did the energy of the electron change?
If the change in energy of electron is totally exhibited as a photon then the energy = h times frequency. h = 6.626 x 10 to -34 J s Simply multiply h and frequency you would get the energy in joule
An electron loses 2.5 x 10-15 J of energy and emits a photon What is the frequency of the photon that is emitted?
Photon energy = (Planck's konstant) x (frequency) nu = E / h E = 2.5 x 10-15 J h = 6.626 x 10-34 J-s nu = (2.5 x 10-15 J) / (6.626 x 10-34 J-s) = (2.5 x 10-15 / 6.626 x 10-34) (J / J - s) = 3.773 x 1019 Hz = 3.773 x 1010 GHz
What is the frequency of a photon with energy of 3.0 x 1013 eV?
The frequency of a photon can be calculated using the formula: E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Converting the energy to Joules gives E = 4.8 x 10^-19 J. Plugging in these values, we find that the frequency of the photon is approximately 7.36 x 10^22 Hz.
What is the frequency of a radar photon with energy 6.80x10 J?
The frequency of a photon is given by dividing its energy by Planck's constant (6.63 x 10^-34 J·s). So, for a photon with an energy of 6.80 x 10^-19 J, the frequency would be (6.80 x 10^19 J) / (6.63 x 10^-34 J·s) = approximately 1.03 x 10^14 Hz.
What is the frequency of a photon with an energy of 3.38 10-19j?
The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J*s), and f is the frequency. Rearranging the formula to solve for frequency gives f = E / h. Plugging in the values, we find that the frequency of a photon with an energy of 3.38 x 10^-19 J is approximately 5.10 x 10^14 Hz.
How to Put these photons in order of increasing energy?
To arrange photons in order of increasing energy, you can use the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. Photons with higher frequency will have higher energy. So, simply compare the frequencies of the photons to determine their energy order.
What is the energy of a microwave photon that has a frequency of 1.12x1012?
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626x10^-34 J*s) and f is the frequency of the photon. Plugging in the values, the energy of a microwave photon with a frequency of 1.12x10^12 Hz is approximately 7.41x10^-22 J.
What is the frequency (s-1) of a photon that has an energy of 4.38 x 10-18 J?
The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency. Rearranging the formula to solve for frequency, we get f = E / h. Plugging in the values, the frequency of a photon with an energy of 4.38 x 10^-18 J is approximately 6.61 x 10^15 s^-1.
What is the frequency of a photon with an energy of 199 x 10 19 J?
The energy of a photon is given by ( E = hf ), where ( h ) is the Planck constant and ( f ) is the frequency of the photon. Rearranging the formula gives ( f = E / h ). Plugging in the given energy value and the Planck constant, the frequency of the photon is approximately 3.01 x 10^22 Hz.
