The frequency of red light with a wavelength of 700 nm can be calculated using the formula: frequency = speed of light / wavelength. Plugging in the values (speed of light = 3.00 x 10^8 m/s), we get a frequency of approximately 4.29 x 10^14 Hz.
The longest visible wavelength of light appears red. "Longest wavelength" is equivalent to 'lowest frequency'.
The wavelength of red light is typically around 700 nanometers (nm) in the visible spectrum.
Shorter wavelengths correspond to higher frequencies, so violet light has a shorter wavelength and higher frequency than red light. In the visible spectrum, red light has the longest wavelength and lowest frequency, while violet light has the shortest wavelength and highest frequency.
Red light has a longer wavelength than blue light, (i.e. greater distance for one oscillation of red light compared to blue light) so there are less oscillations in the same period of time for red light, and thus red light has a lower frequency than blue light. More concisely: Wavelength = Wavespeed / Frequency , where wavespeed is constant So Frequency = Wavespeed / Wavelength Therefore as wavelength increases, frequency decreases. Make sense? Jack
Yes, the frequency of light increases from red to violet. Red light has the longest wavelength and lowest frequency, while violet light has the shortest wavelength and highest frequency in the visible spectrum.
The longest visible wavelength of light appears red. "Longest wavelength" is equivalent to 'lowest frequency'.
Red light has a longer wavelength and lower frequency compared to blue light. Blue light has a shorter wavelength and higher frequency, which is why it appears bluer in color to the human eye.
The longest wavelength / lowest frequency visible light is the red end of the spectrum. The shortest wavelength / highest frequency visible light is the violet end of the spectrum.
The wavelength of red light is typically around 700 nanometers (nm) in the visible spectrum.
Its frequency (wavelength).
Shorter wavelengths correspond to higher frequencies, so violet light has a shorter wavelength and higher frequency than red light. In the visible spectrum, red light has the longest wavelength and lowest frequency, while violet light has the shortest wavelength and highest frequency.
Ok, so this goes back to the inverse relationship between wavelength and frequency ( energy). As wavelength increases , frequency decreases, the relationship between the two is a inverse relationship. the Red light, wavelength of approx. 700 m^-7 , has a greater wavelength then of the blue light, 400m ^-7. This means , due to frequency and wavelength having an inverse relationship, blue light has a greater frequency (energy) than red light. This is why blue light, no matter how dim, will impart more energy to an electron , then a red light would.
Because red light has minimum frequency and thus it has maximum wavelength.
The frequency of red light is lower than the frequency of violet light. This is because red light has a longer wavelength, which corresponds to a lower frequency. This difference in frequency is what causes red light to be more common than violet light in natural light sources.
No, red is the longest wavelength of visible light, with the lowest frequency and the least energy. Violet light has the shortest wavelenght, with the highest frequency and the most energy (of visible light).
Red light has a longer wavelength than blue light, (i.e. greater distance for one oscillation of red light compared to blue light) so there are less oscillations in the same period of time for red light, and thus red light has a lower frequency than blue light. More concisely: Wavelength = Wavespeed / Frequency , where wavespeed is constant So Frequency = Wavespeed / Wavelength Therefore as wavelength increases, frequency decreases. Make sense? Jack
Yes, the frequency of light increases from red to violet. Red light has the longest wavelength and lowest frequency, while violet light has the shortest wavelength and highest frequency in the visible spectrum.