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The gauge pressure of seawater at a depth of 250m is approximately 24.5 atm. This can be calculated using the formula P = ρgh, where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth.

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1y ago

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How much work must be done to lift the beam 290m?

The amount of work done to lift an object is equal to the force applied multiplied by the distance over which the force is applied. Without information about the force or mechanism used to lift the beam, it is not possible to calculate the work done.


A ball starts at rest accelerates uniformly and travels 250m in 5 seconds What is the final velocity and the acceleration of the ball?

Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !


What is the acceleration of a 200g object experiencing a 50N force?

200N doesn't describe the object, it describes the force acting on an object. If i can correctly assume you are talking about 200N as the weight force of the object, F=MA 200=M(9.8) M=200/9.8 M= a little bit more than 2kg


If A 130 N suitcase is dragged a distance of 250m at a constant speed A force of 60 N is exerted at an angle 40 degrees above the horizontal. a How much work is being done. b How much work is done?

The force which is responsible to make a drag through a distance of 250 m is the horizontal component of the force 60 N ie 60 cos 40 = 45.96 N Hence the work done = F s = 45.96 x 250 = 11490 joule. The usual formula for work done W = F s cos@ where @ is the angle between the force vector and the displacement vector. Here the weight of the suitcase is perpendicular to the displacement and so the value of cos 90 is zero and hence no work is done due to the weight of the suitcase.