The height of the object can be calculated using the kinematic equation:
h = (vf^2 - vi^2) / (2g)
where h is the height, vf is the final velocity (0 m/s at ground level), vi is the initial velocity (10 m/s), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values gives:
h = (0 - 10^2) / (2 * 9.8) = -51.02 meters
The negative sign indicates that the object is below the reference point, so the height is 51.02 meters.
The gain velocity per second for a freely falling object is approximately 9.81 meters per second squared, which is the acceleration due to gravity on Earth. This means that the object's velocity increases by 9.81 meters per second for every second it falls.
When an object is dropped from a certain height, it accelerates towards the ground at a rate of approximately 9.81 meters per second squared on Earth due to gravity. This acceleration remains constant throughout the object's fall, disregarding air resistance.
Use the formula potential energy = mgh (mass x gravity x height), mass in kilograms, gravity about 9.8 (meters per square second), height in meters. Answer will be in Joules.
The acceleration of the object is the rate at which its velocity changes over time, measured in meters per second squared.
10 meters/second2 refers to an acceleration. It is the same as 10 (meters/second) / second, and means that every second, the speed changes by 10 meters/second.
20 meters per second
The speed of an object falling from a great height is measured in meters per second per second until it reaches terminal velocity (maximum downward speed).
per second per second is taken with the context of how an object is changing its acceleration. An object accelerates by speeding up or slowing down. If an object speeds up, it could speed up at a rate of 5 meters per hour, let's say, every second. So after one second, its speed is 5 mph; after two seconds, its speed is 10 mph and so forth. If an object's speed is increasing at 5 meters a second, then its speed is 5 meters per second the first second; 10 meters per second the second second and so forth. We would say the object's acceleration is 10 meters per second / per second.AnswerIt has to do with speed,the time an object falls from a given height is calculated in seconds per second( it fell in less than a second)
It depends on the height of the building and also on the direction the object is thrown in (up, down etc.).
This is completely unrelated to the height. An object at that mass, and speed, can be at any height.This is completely unrelated to the height. An object at that mass, and speed, can be at any height.This is completely unrelated to the height. An object at that mass, and speed, can be at any height.This is completely unrelated to the height. An object at that mass, and speed, can be at any height.
593 meters.
1000000 m
The gain velocity per second for a freely falling object is approximately 9.81 meters per second squared, which is the acceleration due to gravity on Earth. This means that the object's velocity increases by 9.81 meters per second for every second it falls.
When an object is dropped from a certain height, it accelerates towards the ground at a rate of approximately 9.81 meters per second squared on Earth due to gravity. This acceleration remains constant throughout the object's fall, disregarding air resistance.
The height ( h ) of the object at time ( t ) can be modeled by the equation ( h(t) = -4.9t^2 + 5t ), where ( t ) is the time in seconds. This equation represents the object's height over time while it reaches its highest point at 2 meters after 0.5 seconds, then falls back down due to gravity.
Use the formula potential energy = mgh (mass x gravity x height), mass in kilograms, gravity about 9.8 (meters per square second), height in meters. Answer will be in Joules.
The object will be moving at 14.7 meters per second. 1.5 seconds X 9.8 meters per second squared(the gravitational constant). This assumes that the object's original velocity is zero.