To find the instantaneous acceleration of a particle, you would need to know the rate of change of its velocity at that specific moment in time. This can be calculated using calculus by taking the derivative of the velocity function with respect to time. The instantaneous acceleration provides information about how the velocity of the particle is changing at that precise instant.
The instantaneous acceleration of the particle is equal to 0 when the velocity of the particle is at a maximum or minimum. This occurs at the points on the graph where the slope of the velocity-time graph is horizontal or the velocity reaches a peak or trough.
False. In uniform circular motion, the instantaneous acceleration is directed towards the center of the circle, which is called the centripetal acceleration. This acceleration is responsible for changing the direction of the velocity of the particle, even though its speed remains constant.
To find the instantaneous acceleration at t = 45.0s, you need to differentiate the velocity function with respect to time. The acceleration at t = 45.0s is the derivative of the velocity function at that time. Apply the derivative to the velocity function to find the acceleration at t = 45.0s.
True. In uniform circular motion, the particle's velocity is tangential to the circular path, and the acceleration is directed radially inward, towards the center of the circular path. This centripetal acceleration causes the change in direction of the particle's velocity, but the magnitude of the velocity remains constant.
If the average acceleration is zero, it means that the object's velocity is not changing over time. Since instantaneous acceleration is the acceleration at a specific moment in time, it can still have a non-zero value depending on the instantaneous velocity of the object at that moment.
The instantaneous acceleration of the particle is equal to 0 when the velocity of the particle is at a maximum or minimum. This occurs at the points on the graph where the slope of the velocity-time graph is horizontal or the velocity reaches a peak or trough.
False. In uniform circular motion, the instantaneous acceleration is directed towards the center of the circle, which is called the centripetal acceleration. This acceleration is responsible for changing the direction of the velocity of the particle, even though its speed remains constant.
To find the instantaneous acceleration at t = 45.0s, you need to differentiate the velocity function with respect to time. The acceleration at t = 45.0s is the derivative of the velocity function at that time. Apply the derivative to the velocity function to find the acceleration at t = 45.0s.
True. In uniform circular motion, the particle's velocity is tangential to the circular path, and the acceleration is directed radially inward, towards the center of the circular path. This centripetal acceleration causes the change in direction of the particle's velocity, but the magnitude of the velocity remains constant.
If the average acceleration is zero, it means that the object's velocity is not changing over time. Since instantaneous acceleration is the acceleration at a specific moment in time, it can still have a non-zero value depending on the instantaneous velocity of the object at that moment.
To find the instantaneous angular acceleration, you need to know the time rate of change of the instantaneous angular velocity. Without this information, you cannot calculate the instantaneous angular acceleration at t=5.0s.
Average acceleration is the average of the accelerations acquired in the whole journey by a body while instantaneous acceleration is the acceleration of the body at any particular instant of time.
no.
Average acceleration will be equal to instantaneous acceleration when an object has an uniform acceleration throughout its motion. Example : A car accelerating at 1m/s2 uniformly in a straight line.
Acceleration is a vector, so it has both magnitude and direction.A particle in the simple harmonic motion, x = a cos(2t), has an acceleration that varies between positive and negative extremes (+4a and -4a) at the end points of its motion and has zero acceleration as it passes through its center of motion.Here is the mathematics.Position ' x ' = a cos(2t)Velocity ' v ' = dx/dt = -2a sin(2t)Acceleration = dv/dt = -4a cos(2t)The minimum instantaneous magnitude of acceleration is zero,and its most negative instantaneous value is [ -4a ].
instantaneous acceleration is the acceleration at one point. yeah, it's true
Instantaneous acceleration and average acceleration are the same when an object's acceleration is constant over the entire time interval being considered. This means that the object's velocity is changing at a constant rate, resulting in both the instantaneous and average accelerations being equal.