The kinetic energy of an object just before it hits the ground is equal to the work done on it by gravity during its fall. This energy is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity before impact.
When a falling stone hits the ground, its kinetic energy is mostly converted into sound energy, heat energy, and some energy used to break pieces of the ground.
260 J. At the point of release, assuming the boulder is stationary before release, its potential energy is 260 J and its kinetic energy is zero. As it falls, the potential energy is converted into kinetic energy, but energy is neither gained nor lost, so at the point of contact with the ground its potential energy is zero and its kinetic energy is 260 J. If you want to be particularly critical, it could be argued that during the fall some energy is expended in displacing the air, but for a boulder the amount of energy expended would be a very small proportion of the total.
When a ball hits the ground, the potential energy it had due to its height is converted into kinetic energy as it falls. Upon impact, some of this kinetic energy is transferred into sound and heat energy through the compression of the ball and ground.
You can calculate the kinetic energy just before hitting the ground using the formula for potential energy and kinetic energy. First, calculate the potential energy at the initial height using mgh (mass x gravity x height). Then equate this value to the kinetic energy just before hitting the ground using the formula 1/2mv^2 (0.5 x mass x velocity squared) and solve for the velocity.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
When a falling stone hits the ground, its kinetic energy is mostly converted into sound energy, heat energy, and some energy used to break pieces of the ground.
Sitting on the table the stone has potential energy, relative to the ground, of weight times height, mgh. It has zero kinetic energy so its total energy is E = 0 + mgh. When it begins falling it loses potential energy (as it loses height) and gains kinetic energy ( as it picks up speed) so the sum stays the same as initially E = KE + PE = mgh. Just before it hits the ground all of its potential energy is gone and has been transformed into kinetic energy. So the kinetic energy at the bottom (1/2)mv^2 will equal the potential energy at the top.
260 J. At the point of release, assuming the boulder is stationary before release, its potential energy is 260 J and its kinetic energy is zero. As it falls, the potential energy is converted into kinetic energy, but energy is neither gained nor lost, so at the point of contact with the ground its potential energy is zero and its kinetic energy is 260 J. If you want to be particularly critical, it could be argued that during the fall some energy is expended in displacing the air, but for a boulder the amount of energy expended would be a very small proportion of the total.
When a ball hits the ground, the potential energy it had due to its height is converted into kinetic energy as it falls. Upon impact, some of this kinetic energy is transferred into sound and heat energy through the compression of the ball and ground.
The acorn has the greatest potential energy at the highest point in its fall, where it is furthest from the ground. As it falls, this potential energy converts into kinetic energy, which is greatest just before it hits the ground. At this moment, the acorn's speed is at its maximum, resulting in the highest kinetic energy.
You can calculate the kinetic energy just before hitting the ground using the formula for potential energy and kinetic energy. First, calculate the potential energy at the initial height using mgh (mass x gravity x height). Then equate this value to the kinetic energy just before hitting the ground using the formula 1/2mv^2 (0.5 x mass x velocity squared) and solve for the velocity.
The ball dropped from 4m height has more kinetic energy just before it hits the ground because it has a higher velocity due to falling from a greater height. Kinetic energy is directly proportional to both mass and the square of velocity, so the ball dropped from 4m height will have more kinetic energy than the one dropped from 2m height.
When a falling rock hits the ground, its potential energy is converted to kinetic energy as it accelerates towards the ground. Upon impact, some of the kinetic energy is transformed into sound energy, heat energy due to friction, and deformation energy as the rock changes shape upon collision with the surface.
When a book falls off a shelf and hits the ground, its potential energy is converted to kinetic energy as it falls. When it hits the ground, some of the kinetic energy is converted into sound and heat energy due to the impact.
Well i think there is nothing good or bad about kinetic energy, because its just something in motion like if you drop a pen that pen was in motion before it hits the ground
In football, potential energy is stored in the ball when it is lifted off the ground before a pass or a kick. When the ball is in motion, it converts this potential energy into kinetic energy. Kinetic energy is what allows the ball to travel through the air and upon impact with a player or the ground.
As the baseball is falling, it still has a lot of the kinetic energy that it got from the bat, and it keeps picking up more kinetic energy from gravity until it hits the ground. Once it hits the ground and rolls, it steadily loses kinetic energy to push grass out of the way, and to slightly heat some grass with friction by rubbing against it, until its kinetic energy is all used up and it stops rolling.