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Kinetic energy is equals to 0.5mv² where m is the mass in kilograms and v is the velocity in ms-1
So, for a bicycle of 10kg moving at 10ms-1,
K.E
= 0.5mv²
= 0.5(10)(10²)
= 500 J
KE = 1/2 M V2 = 1/2 (10) (10)2 = 500 kg-m2/s2 = 500 joules
500 J
The formula for kinetic energy is (1/2) x mass x velocity2. If mass is in kg. and speed in meters per second, the energy will come out in Joule.D. 125 J
The potential energy you mentioned is known as gravitational potential energy, which involves gravity. Gravity is a wonderful mechanism which acts like a rubberband. Let say the object is you riding a bicycle. To climb a hill, you need to input your kinetic energy which is to pedal hardly to increase your altitude(height). When you are at the top of the hill(summit), you have the greatest gravitational potential energy. What is the difference between you at the bottom of the hill and you at the top of the hill? The you at the summit has stored more energy in your mass, which can be converted only into kinetic energy when you roll down the hill.
Doubling mass affects kinetic energy in that the greater the mass, the greater the kinetic energy. OK, but if you have a 10kg mass traveling at 2m/s and it bumps into and sticks to a 10g mass, the resultant speed would be 1m/s. The momentum stays the same. KE before is 10*2*2/2= 20, while the KE after is 20*1*1/2= 10. So it is not that the above answer is wrong, but rather, you question is not clear.
K= 1/2mv2 eg. 10kg, 30mph convert speed into meter/second 30mph = 13.4112m/s so, half of mass = 5 multiplied by the velocity squared 0.5 x 10 x (13.41122) =899.3014272 joule
Momentum = Mass x Velocity = 11 x 10 = 110 Ns (Newton seconds)
Ke=½MV² Kinetic Energy equals one half the mass of the object multiplied by the square of the velocity. If the object weighs 10kg moving at 5 meters per second... ½10 = 5 5² = 25 5 x 25 = 125 has a kinetic energy of 125 Joules
The formula for kinetic energy is (1/2) x mass x velocity2. If mass is in kg. and speed in meters per second, the energy will come out in Joule.D. 125 J
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
The exact method depends on how the question is phrased, but the majority of solutions will involve a conservation of energy. Since the energy of a system must always be conserved, you can determine the change in an objects kinetic energy by measuring how much potential energy it has lost. The most common examples include gravitational potential energy and free fall. For example, say you wanted to find the kinetic energy of a 10kg rock after it has fallen off a cliff 200m high once it has fallen 100 meters. First, you use the formula PE=m*g*h (where m is mass, g is the acceleration due to gravity, 9.81 m/s², and h is the distance above ground). At the top the rock is 200m up, so its potential energy is 10kg*9.81m/s²*200m = 19620J. When the rock has fallen 100 meters, it is 100 meters up, so its potential energy is 10kg*9.81m/s²*100m = 9810J. Now, to find how much kinetic energy the rock has, just calculate the change in potential energy or 19620J-9810J=9810J. The same process can be used when working with chemical, electric, or any other form of potential energy. Alternatively, you could use the definition of Work=Force * Distance if you are given that information instead. For example, if you apply a 5 Newton force over 20 meters, 5N*20m=100J of work done which is all gained by the object being pushed on.
The potential energy you mentioned is known as gravitational potential energy, which involves gravity. Gravity is a wonderful mechanism which acts like a rubberband. Let say the object is you riding a bicycle. To climb a hill, you need to input your kinetic energy which is to pedal hardly to increase your altitude(height). When you are at the top of the hill(summit), you have the greatest gravitational potential energy. What is the difference between you at the bottom of the hill and you at the top of the hill? The you at the summit has stored more energy in your mass, which can be converted only into kinetic energy when you roll down the hill.
Doubling mass affects kinetic energy in that the greater the mass, the greater the kinetic energy. OK, but if you have a 10kg mass traveling at 2m/s and it bumps into and sticks to a 10g mass, the resultant speed would be 1m/s. The momentum stays the same. KE before is 10*2*2/2= 20, while the KE after is 20*1*1/2= 10. So it is not that the above answer is wrong, but rather, you question is not clear.
Fusing 10 kg of hydrogen -apex
K= 1/2mv2 eg. 10kg, 30mph convert speed into meter/second 30mph = 13.4112m/s so, half of mass = 5 multiplied by the velocity squared 0.5 x 10 x (13.41122) =899.3014272 joule
Both the 10kg stack of books and the 10kg piece of Styrofoam weigh the same amount, 10kg, because weight is a measure of the force due to gravity acting on an object's mass.
When the pendulum is at it's highest point in it's path of flight, the pendulum is not moving, and has purely potential energy. When the pendulum reaches the lowest point in it's flight, that potential energy is converted into kinetic. The total amount of energy has not changed though. Let's make up numbers to prove how this is true. Say we have a ball on the end of the pendulum that weighs 10kg. At it's max height, the ball reaches 5 meters above it's starting point. Since potential energy (PE) = mass (m) x gravity (g) x height (h), our PE = (5kg)(10m/s^2)(5m) = 250 Joules. As I mentioned earlier, total potential energy will equal the total kinetic energy (KE). When the ball reaches it's lowest point (where it's velocity is the highest), we can use our PE energy from the first equation to determine how fast the ball is moving at the bottom of the swing. KE = (1/2) x mass (m) x velocity (v) squared. Since KE also equals PE, we have 250 = (1/2)(5)(v^2) --> 100 = v^2. Therefore the veolcity equals 10 meters per second.
Momentum = Mass x Velocity = 11 x 10 = 110 Ns (Newton seconds)
It would weigh 10kg.