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If molybdenum is irradiated with light of a wavelength of 122 nm what is the maximum possible kinetic energy of the emitted electrons?
The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.
Why the kinetic energy of the emitted electrons varies up to a maximum value?
Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)
What is the relationship between frequency and kinetic energy in photoelectric effect?
In the photoelectric effect, increasing the frequency of incident light increases the kinetic energy of the emitted electrons. This is because higher frequency light photons carry more energy, which can be transferred to the electrons during the photoelectric effect.
What does light do in photoeletric effect?
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
What 3 experimental facts about the photoelectric effect could only be explained by the idea of atoms absorbing photons of lights of a certain energy?
The existence of a threshold frequency below which no electrons were emitted. The direct proportionality between the frequency of incident light and the kinetic energy of emitted electrons. The instantaneous emission of electrons once the threshold frequency was surpassed, rather than a delayed response as would be expected in a classical wave model.
What is the kinetic energy of the emitted electrons when the cesium is exposed to UV rays of frequency 1.1times 1015Hz?
Before you can do anything with kinetic energy, you must know the kinetic energy equation. The equation for kinetic energy KE=hv-hv0.
What is the relationship between maximum frequency and maximum kinetic energy in photoelectric effect?
In the photoelectric effect, the maximum kinetic energy of emitted electrons is directly related to the frequency of the incident light. According to Einstein's photoelectric equation, the maximum kinetic energy (K.E.) of the electrons is given by ( K.E. = hf - \phi ), where ( h ) is Planck's constant, ( f ) is the frequency of the light, and ( \phi ) is the work function of the material. As the frequency increases, the maximum kinetic energy of the emitted electrons also increases, provided the frequency exceeds the threshold frequency necessary to release electrons. Thus, higher frequencies lead to greater maximum kinetic energies of the emitted electrons.
If molybdenum is irradiated with light of a wavelength of 122 nm what is the maximum possible kinetic energy of the emitted electrons?
The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.
Why the kinetic energy of the emitted electrons varies up to a maximum value?
Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)
What is the relationship between frequency and kinetic energy in photoelectric effect?
In the photoelectric effect, increasing the frequency of incident light increases the kinetic energy of the emitted electrons. This is because higher frequency light photons carry more energy, which can be transferred to the electrons during the photoelectric effect.
What does light do in photoeletric effect?
In the photoelectric effect, light (photons) ejects electrons from a material's surface, creating an electric current. The energy of each photon must exceed the material's work function for electrons to be emitted. The intensity of light affects the number of electrons emitted, while the frequency determines the kinetic energy of the emitted electrons.
What 3 experimental facts about the photoelectric effect could only be explained by the idea of atoms absorbing photons of lights of a certain energy?
The existence of a threshold frequency below which no electrons were emitted. The direct proportionality between the frequency of incident light and the kinetic energy of emitted electrons. The instantaneous emission of electrons once the threshold frequency was surpassed, rather than a delayed response as would be expected in a classical wave model.
What do scientist using classical Newtonian expect to observe during a photoelectric effect?
Scientists using classical Newtonian physics would expect to observe a gradual increase in the kinetic energy of emitted electrons when exposed to increasing light intensity in the photoelectric effect. They would also expect the emission of electrons to start immediately upon exposure to light, regardless of its frequency.
What are the Differences between thermionic emission and photoelectric emission?
Electrons would have enough energy to leave the metal surface, the hot cathode. However, without the forward voltage bias, positive anode. The vacuum diode could not conduct electricity. In other words, the initial kinetic energy of the emitted electrons can be ignored [0 J].Whereas, the photo-emitted electrons possess definite amount of initial kinetic energy.K.E. of e = hf - WorkFunctionSee, the initial k.e. is not neglectable.
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.41015Hz Express your answer in joules to three significant figures.?
The kinetic energy of the emitted electrons can be calculated using the formula: (KE = hf - \phi), where (h) is Planck's constant ((6.626 x 10^{-34} J\cdot s)), (f) is the frequency of the UV rays (1.41 x 10^15 Hz), and (\phi) is the work function of cesium (1.93 eV = 3.088 x 10^-19 J). Plugging in the values, we get KE = (6.626 x 10^-34 J*s x 1.41 x 10^15 Hz) - 3.088 x 10^-19 J, which is approximately equal to 9.30 x 10^-19 J.
When a clean surface of potassium metal is exposed to blue light electrons are emitted if the intensity of the blue light is increased what will also increase?
i have the same question on my test haha for me, the answers are: a) The number of electrons ejected per second b) the maximum kinetic energy of the ejected electrons c) the threshold frequency of the ejected electrons d) the time lag between the absorption of blue light and the start of emission of the electrons e) none of these A the number of electrons ejected per second,,,,, correct answer
What will happen if monochromatic light is shining on the alkali metal and the cesium is just above the threshold frequency?
If monochromatic light is shining on an alkali metal and cesium is just above the threshold frequency, electrons in the cesium atoms will be ejected in a process called the photoelectric effect. These ejected electrons will have kinetic energy equal to the difference between the energy of the incident photon and the work function of the metal. The photoelectrons will be emitted instantaneously.
