use simple pendulum formula T=2pie/square root L over g(where L is the length of pendulum,T is time period,and g is gravitational acceleration normally taken as 9.81) .then square both sides to get rid of square root.answer is 1.998476789 meters which is 2.0 to two significant figures.
16 years = 504,910,816 seconds.
1000 seconds = 16.6666667 minutes
Period = 1/frequency = 1/60 = 16 and 2/3 milliseconds
A kilosecond, but the terminology isn't used often
Average speed = (total distance) / (total time for the distance) =(16 + 16) / (4 + 2) = (32/6) = 51/3 meters per second
To find the period of a pendulum, you divide the total time by the number of cycles. In this case, the total time is 48 seconds for 16 cycles. Thus, the period ( T ) is calculated as ( T = \frac{48 , \text{seconds}}{16} = 3 , \text{seconds} ). Therefore, the period of the pendulum is 3 seconds.
The longer the pendulum is, the greater the period of each swing. If you increase the length four times, you will double the period. It is hard to notice, but the period of a pendulum does depend on the angle of oscillation. For small angles, the period is constant and depends only on the length of the pendulum. As the angle of oscillation (amplitude) is increased, additional factors of a Taylor approximation become important. (T=2*pi*sqrt(L/g)[1+theta^2/16+...] and the period increases. (see hyper physics: http://hyperphysics.phy-astr.gsu.edu/hbase/pendl.html) Interestingly, if the pendulum is supported by a very light wire then the mass of the object at the end of the pendulum does not affect the period. Obviously, the greater the mass, the less any air friction or friction at the pivot will slow the pendulum. Also interestingly, the pendulum period is dependant on the force of gravity on the object (g). One must not assume that g is constant for all places on Earth.
The closest planet to Earth in terms of rotation period is Mars with a period of 24 hours 37 minutes 23 seconds. The second closest is Neptune at 16 hours.
The length of a day on Neptune is approximately 16 hours (16 hours 3-6 minutes at last estimate August 2007).
Pendulum - 2001 is rated/received certificates of: Germany:16 Iceland:16 USA:R
The Sidereal rotational period (one spin relative to the background stars) is 16 hrs 6 min and 36 seconds. This is approximately the length of one Neptuniuan day. The length of one Neptunian year (one rotation around the sun) is 164.79 years.
Pendulum - 1969 is rated/received certificates of: Finland:K-16 Iceland:16 Norway:16 (1970) Sweden:15 UK:15 USA:PG USA:M (original rating)
16 years = 504,910,816 seconds.
There are 60 seconds in a min. Therefore 16 mins will have 16*60 seconds in it ..... I will let you do the multiplication.
16 weeks = 9,676,800 seconds.
16 hours has 57,600 seconds.
18.4