The magnitude of the vector 3i + 4j is given by the formula |v| = sqrt((3^2) + (4^2)) = sqrt(9 + 16) = sqrt(25) = 5. Therefore, the magnitude of the vector is 5.
α = (Fr sinθ)/m where F is the force acting on the object ..........r is the radius from the 'centre' of the object to the point of application of force. ..........θ is the angle between r and the vector of the force. ..........m is the moment of inertia of the object.
No it isn't. Motion means something moving.Direction has to be established for there to be a change in it. An object that moves forward, stops, and then moves forward again experiences motion without a change in direction. An object that moves forward, stops, and then moves to the right experiences both motion and a change in direction.
The potential difference is 1 volt. This is because potential difference is given by the formula V = W / Q, where V is the potential difference, W is the work done (energy) moving the charge, and Q is the charge. In this case, V = 4 J / 4 C = 1 V.
To calculate the energy released when the copper cools from 1083°C to 25°C, you need to use the formula: Q = mcΔT, where Q is the energy released, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the change in temperature. First, find the change in temperature: ΔT = 1083°C - 25°C = 1058°C. Now plug in these values into the formula: Q = 28.9g * 385 J/g°C * 1058°C. Calculate the energy released in Joules.
42 j
The magnitude of a vector can be found by taking the square root of each of the vector components squared. For example, if you had the vector 3i+4j, to find the magnitude, you take sqrt ( 3²+4² ) To get: sqrt ( 9+16 ) sqrt ( 25 ) = 5 Works the same in 3D or more, just put all the vector components in.
7
To find the magnitude of the resultant displacement (\mathbf{R} = \mathbf{A} + \mathbf{B}), we first add the vectors: [ \mathbf{R} = (5i - 23) + (-3i + 4j + 6k) = (5 - 3)i + 4j + 6k - 23 = 2i + 4j + 6k - 23. ] This simplifies to (\mathbf{R} = 2i + 4j - 17). The magnitude of (\mathbf{R}) is given by: [ |\mathbf{R}| = \sqrt{(2)^2 + (4)^2 + (-17)^2} = \sqrt{4 + 16 + 289} = \sqrt{309} \approx 17.578. ] Thus, the magnitude of the resultant displacement is approximately 17.58 m.
Assuming you mean:F1 = 3i - 4j + 2k,F2 = 2i + 3j - k,F3 = 2i + 4j - 5k.Simply add all of them algebraically, i.e. add i's to i's, j's to j's etc. - this works in all dimensions.The resultant force F will be in your case:F = 7i + 3j - 4k.
-4j-1-4j+6 = -8j+5
I've got to assume that your ' i ' and your ' j ' are the same thing.Vector A = j3Vector B = -j1The angle between them is (pi).
If: j = 20-4j Then : j = 4
Express one variable in terms of the other. 3Y - 4J = 9 3Y = 4J + 9 Y = (4J + 9)/3 ------------------------ insert back into original equation 3(4J + 9)/3 = 9 you see the 3 factors cancel 4J + 9 = 9 4J = 0 J = 0 -------------you have J 3Y - 4(0) = 9 3Y = 9 Y = 3 ----------------one set of solutions to this problem
I think you have entered the inequality wrong. You have: 4j - 7 > 4j - 7 but that is saying that something is greater than itself as both sides of the greater than sign are the same expression.
4j it would be 'j squared' if it was jxjxjxj
4j
α = (Fr sinθ)/m where F is the force acting on the object ..........r is the radius from the 'centre' of the object to the point of application of force. ..........θ is the angle between r and the vector of the force. ..........m is the moment of inertia of the object.