That depends on where the charges are, and the magnitude of the charges. In general, you must calculate the vector for the force due to each individual charge, then add all the vectors together.
I'm not sure what this question really means - should it be more like "what two things affect the force between two electric charges?" If this is correct then the answer is probably: 1. The amount of charges. 2. The distance between the charges.
An electric field surrounds the charge and exerts force on other charges.
Electric force is the force applied on 2 electric charges, by those 2 electric charges.
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
An electric field surrounds the charge and exerts force on other charges.
I'm not sure what this question really means - should it be more like "what two things affect the force between two electric charges?" If this is correct then the answer is probably: 1. The amount of charges. 2. The distance between the charges.
Hello, some error in the words. Electric "force" not electric charge. A/s we increase the distance between the charges ./2 times then force between them will be halved.
An electric field surrounds the charge and exerts force on other charges.
Electric force is the force applied on 2 electric charges, by those 2 electric charges.
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
An electric field surrounds the charge and exerts force on other charges.
An electric field has both magnitude and direction and can be represented by lines of force, or field lines, that start on positive charges and terminate on negative charges.
Coulomb's Law states that the magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each charge and inversely proportional to the square of the distance between the charges. A link is provided to the Wikipedia article.
Because of the electric force and stuff and the magnitude and lattitude that pulls it across the system of rods
Assuming that the only force on the two objects is an electric force. Felectric = k Q q / r2 This is Coulomb's law. K = electrostatic constant, Q and q are the magnitudes of the point charges, and r is the distance between the point charges. As you can see, if you decrease the magnitude of the charge, the electric force decreases. In other words, the objects are less attracted to one another. aside: gravity happens to be modeled the same way.
Experiments have shown that the electric force between two objects is proportional to the inverse square of the distance between the two objects. The electric force between two electrons is the same as the electric force between two protons when they are placed as the same distance. This implies that the electric force does not depend on the mass of the particle. Instead, it depends on a new quantity: the electric charge. The unit of electric charge q is the Coulomb (C). The electric charge can be negative, zero, or positive. The electric charge of electrons, protons and neutrons are -1.6 x 10-19, 1.6 x 10-19, and 0. Detailed measurements have shown that the magnitude of the charge of the proton is exactly equal to the magnitude of the charge of the electron. Since atoms are neutral, the number of electrons must be equal to the number of protons. The precise magnitude of the electric force that a charged particle exerts on another is given by Coulomb's law.
I dont know haha you tell me.