If 96.5 g balances the object, then the mass of the object must also be 96.5 g. This is because in order for an object to balance on a scale, the total mass on both sides of the scale must be equal.
The density of the gold nugget is 19.3 g/cm^3. This was calculated by dividing the mass (965 g) by the volume (50 cm^3).
965 g is a measure of mass, and 50 cm is a measure of length. They are two different physical quantities and cannot be directly converted into each other.
The density of the object is 3.68 g/cm³. Density is calculated by dividing the mass of the object by its volume. In this case, 184 g ÷ 50 cm³ = 3.68 g/cm³.
The mass of an object that weighs 200 grams is 200 grams.
The object has a density of 0.7 g/cm3
The density of the gold nugget is 19.3 g/cm^3. This was calculated by dividing the mass (965 g) by the volume (50 cm^3).
965 g is a measure of mass, and 50 cm is a measure of length. They are two different physical quantities and cannot be directly converted into each other.
The quantity measured by a balance is mass, and the unit of measurement is typically grams (g) or kilograms (kg). The balance is used to determine the mass of an object by comparing it to known masses on the opposite side of the balance.
The density is 2,0125 g/cm3.
The S.I unit of mass is kilograms(kg) but you can also use grams(g). To find the mass of an object you can use an electronic balance.
The balance should read 11.25 g. The total mass displayed on the balance is the mass of the sample (11.00 g) plus the mass of the weighing paper (0.25 g) for a total of 11.25 g.
The density of the object can be calculated by dividing its mass (6.118) by its volume (3.04). Density = Mass/Volume Density = 6.118/3.04 Density ≈ 2.015 g/cm³ Therefore, the density of the object is approximately 2.015 g/cm³.
yes
The density of the object is 3.68 g/cm³. Density is calculated by dividing the mass of the object by its volume. In this case, 184 g ÷ 50 cm³ = 3.68 g/cm³.
Yes. You would need some way of keeping the orange on the balance though. I would suggest placing a bowl on the balance, correcting for it's weight, and then measuring the combined weight of bowl and orange.
The mass divided by the volume, v.
0.3456 g