Just use the definition of momentum, as mass x velocity. In this case, you need to divide the momentum by the velocity, to get the mass.
It depends at what time in the throw your talking about. In the beginning it gains momentum, then in the middle it starts to lose momentum then in the end it loses all momentum.
Momentum = (mass) x (speed) = (0.148) x (35) = 5.18 kilogram meters per second
No, because the conservation momentum principle is only valid when none force is applied. And here you have the gravity force.
The highest point is the point where the ball's velocity transitions from upward to downward. At that instant, the ball's speed, velocity, momentum, and kinetic energy are all exactly zero.
m = 4.5kg v = 2.2m/s M = 15kg V = ? ---- velocity of ham and cart before: momentum of ham = pv momentum of cart = 0 after: momentum of ham and cart = (m+M)V momentum of ham + momentum of cart = momentum of ham and cart mv + 0 = (m+M)V mv / (m+M) = V (4.5*2.2) / (4.5 + 15) = 0.51 kgm/s
It depends at what time in the throw your talking about. In the beginning it gains momentum, then in the middle it starts to lose momentum then in the end it loses all momentum.
Momentum = (mass) x (speed) = (0.148) x (35) = 5.18 kilogram meters per second
depends on how fast its thrown. every pitcher has a different speed
ρ=mvρ= 0.130 x 30ρ= 3.9 Kgms-1
A baseball can
No, because the conservation momentum principle is only valid when none force is applied. And here you have the gravity force.
Momentum = (mass) x (speed) = (67 x 23) = 1,541 kg-m/s.
jakob lee Jones
Jim had thrown the baseball into the neighbor's window.
The highest point is the point where the ball's velocity transitions from upward to downward. At that instant, the ball's speed, velocity, momentum, and kinetic energy are all exactly zero.
No
class A