The density of ice is approximately 0.92 g/cm³. The volume of the ice cube with 1 cm sides is 1 cm³. Therefore, the mass of the ice cube is 0.92 grams.
The volume of the cube is calculated by V = s^3 = 4^3 = 64 cm^3. Divide mass by volume to get density: density = mass / volume = 512g / 64 cm^3 = 8 g/cm^3.
The volume of the cube is (3 \times 3 \times 3 = 27 , \text{cm}^3). Density is calculated by dividing mass by volume, so the density of the cube would be (27 , \text{g} \div 27 , \text{cm}^3 = 1 , \text{g/cm}^3).
To find the mass of the ice cube in grams, you first need to convert the side length from inches to centimeters. You would then calculate the volume of the cube by cubing the side length in centimeters. Finally, you would multiply the volume by the density of ice (0.92 g/cm^3) to find the mass in grams.
The volume of the cube is calculated by V = s^3, where s is the side length (5 cm). Therefore, V = 5^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass/volume = 100 g / 125 cm^3 ≈ 0.8 g/cm^3.
The density of the cube is calculated by dividing the mass of the cube by the volume of the cube. The volume of a cube is given by the formula side length cubed, so the density of the cube would be mass (g) divided by side length (cm) cubed.
To calculate the mass of an ice cube measuring 5.80 cm on each side, first find its volume. The volume of a cube is given by ( V = s^3 ), where ( s ) is the side length. For a 5.80 cm cube, the volume is ( 5.80^3 = 195.112 , \text{cm}^3 ). Since the density of ice is approximately 0.92 g/cm³, the mass can be calculated as ( \text{mass} = \text{density} \times \text{volume} ), resulting in a mass of about 179.09 grams.
The capacity of a cubic centimeter (cm³) ice cube is 1 cm³, which is equivalent to 1 milliliter (mL) of water. Since ice has a lower density than liquid water, its mass will be slightly less than 1 gram for the same volume. Therefore, a 1 cm ice cube can hold 1 mL of liquid water when it melts.
Volume of cube = 4 x 4 x 4 = 64 cubic cm Mass = 512 g Density = Mass/Volume = 512/64 = 8 g/cubic cm
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The volume of the cube is calculated by V = s^3 = 4^3 = 64 cm^3. Divide mass by volume to get density: density = mass / volume = 512g / 64 cm^3 = 8 g/cm^3.
To determine if a solid cube with 6-cm sides and a mass of 270 g would float, we need to calculate its density and compare it to the density of water. The volume of the cube is (6 , \text{cm} \times 6 , \text{cm} \times 6 , \text{cm} = 216 , \text{cm}^3). The density of the cube is ( \frac{270 , \text{g}}{216 , \text{cm}^3} \approx 1.25 , \text{g/cm}^3), which is greater than the density of water (1 g/cm³). Therefore, the cube would not float.
The volume of the gold cube is calculated as side cubed (4 cm * 4 cm * 4 cm) = 64 cm^3. Density is mass divided by volume (1235 g / 64 cm^3 ≈ 19.3 g/cm^3). So, the density of the gold cube is approximately 19.3 g/cm^3.
The volume of the cube is (3 \times 3 \times 3 = 27 , \text{cm}^3). Density is calculated by dividing mass by volume, so the density of the cube would be (27 , \text{g} \div 27 , \text{cm}^3 = 1 , \text{g/cm}^3).
To find the mass of the ice cube in grams, you first need to convert the side length from inches to centimeters. You would then calculate the volume of the cube by cubing the side length in centimeters. Finally, you would multiply the volume by the density of ice (0.92 g/cm^3) to find the mass in grams.
3.634 cm
27 cm^3
The surface area of a cube with sides of 4 cm is 6*42 square cm = 96 sq cm. The surface area of a cube with sides of 2 units is 6*22 square units = 24 sq units.