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What is the maximum resultant possible when adding a 3N force to an 8N force?
The maximum resultant possible when adding a 3N force to an 8N force is 11N. This occurs when the two forces are acting in the same direction, resulting in additive effects on the total force magnitude.
What are the maximum and minimum resultant force that can act on the body when two forces of magnitudes 5N and 8N act on body?
maximum resultant: 45 = a + b minimum resultant: 5 = a - b Solve for a in the first equation then substitute it into the second equation: a = 45 - b 5 = 45 - b -b 5 - 45 = -2b -40 = -2b 20 = b Since we know the value for b we can substitute it into the first equation to find the value for a: 45 = a + 20 45 - 20 = a 25 = a So the magnitude of each of these forces are 20N, 25N.
What is the minimum resultant possible when adding a 5-N force to an 8-N force?
3N
What is the minimum resultant possible when adding a 5-N force to an 8 N force?
The maximum resultant occurs when the forces act in the same direction. Its magnitude is 15 N.
What is the example of head to tail rule?
In addition of vector when vector A whose head is joined to the tail of the vector B and then the tail of the vector A is linked with the tail of the resultant vector and the head of the vector B is joined with the head of the resultant vector..... it means the addition of vectors are also defined the head to tail rule..
What is the maximum resultant possible when adding a 3N force to an 8N force?
The maximum resultant possible when adding a 3N force to an 8N force is 11N. This occurs when the two forces are acting in the same direction, resulting in additive effects on the total force magnitude.
What are the maximum and minimum resultant force that can act on the body when two forces of magnitudes 5N and 8N act on body?
maximum resultant: 45 = a + b minimum resultant: 5 = a - b Solve for a in the first equation then substitute it into the second equation: a = 45 - b 5 = 45 - b -b 5 - 45 = -2b -40 = -2b 20 = b Since we know the value for b we can substitute it into the first equation to find the value for a: 45 = a + 20 45 - 20 = a 25 = a So the magnitude of each of these forces are 20N, 25N.
What is the minimum resultant possible when adding a 5-N force to an 8-N force?
3N
What is the minimum resultant possible when adding a 5-N force to an 8 N force?
The maximum resultant occurs when the forces act in the same direction. Its magnitude is 15 N.
If diagram of force is 3n 10n 8n 5n which direction will the object move?
The object will move in the direction of the net force, which is the vector sum of all the forces. In this case, the net force would be 3N + 10N + 8N + 5N = 26N. So, the object will move in the direction of the resultant force, which is 26N.
What is the example of head to tail rule?
In addition of vector when vector A whose head is joined to the tail of the vector B and then the tail of the vector A is linked with the tail of the resultant vector and the head of the vector B is joined with the head of the resultant vector..... it means the addition of vectors are also defined the head to tail rule..
what is (3n)(3n-1)?
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
What is the net force if the box is being pushed to the left with 11N and being pulled to the left with 12N and being pulled to the right with 3N?
The net force is calculated by adding up all the forces acting on the object. In this case, the forces being applied to the left (11N and 12N) are greater than the force being applied to the right (3N). Therefore, the net force would be 11N + 12N - 3N = 20N to the left.
How do you get this 3n plus 2 plus (3n plus 3 - 3n plus 1)?
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
A number is multiplied by 3 if 2 is added to the product you will get -4 so whats the number?
Let the number be n. Then 3n + 2 = -4 3n = -6 n = -3
What is the Greatest Common Factor of 3n2 and 3n?
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
Compare the amount of work done when a force of 2n moves an object 3 meters with the work done when a force of 3n moves an object 2 meters?
When a force of 2N moves an object 3 meters, the work done is 6 Joules (2N * 3m). When a force of 3N moves an object 2 meters, the work done is 6 Joules as well (3N * 2m). Consequently, the same amount of work (6 Joules) is done in both scenarios.
