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What factors have an effect on the maximum velocity at which a vehicule is able to travel on a curve that has no incline?
Factors that affect the maximum velocity on a curve with no incline include the radius of the curve, the coefficient of friction between the tires and the road, and the mass of the vehicle. A tighter curve radius, lower friction, or higher vehicle mass will decrease the maximum velocity the vehicle can safely travel around the curve without skidding.
What is the maximum speed a car can take in a 20m radius curve along a road if the coefficient of static friction between the tyres and the road is 0.60?
The maximum speed a car can take in a 20m radius curve is determined by the centripetal force required to keep the car on the curve. Using the formula Fc = mv^2/r, the maximum speed can be calculated to be approximately 22.58 m/s, or about 81.29 km/h.
If you know the coefficient of friction how do you find the maximum velocity to maintain a circular path at a given radius?
say mass(m) = 10 kg, radius(r) = 10 m, say friction coefficient = 0.5 force to break friction = 10 * 0.5 = 5 kgf = say 50 n to find acceleration required to produce this force use f=m*a, shuffle to a = f / m so a = 50 / 10 = 5 (m/s)/s, install in a = v^2 / r, so 5 = v^2 / 10, so 10 * 5 = v^2, so sq. root 50 = v, so v = 7.07 metres / second if friction coefficient and radius remain the same, altering the mass wont alter the velocity at breakaway point
If a curve with a radius of 60 m is properly banked for a car traveling 60 kmh what must be the coefficient of static friction for a car not to skid when travelling at 90 kmh?
To prevent skidding at 90 km/h, the car would need a coefficient of static friction of at least 0.25. This value can be calculated using the formula: coefficient of friction = tan(theta), where theta is the angle of banking. Given the curve radius, speed, and the formula, we can determine the necessary value for the coefficient of friction.
The maximum speed at which a car can safely negotiate a frictionless banked curve depends on all of the following except?
The maximum speed at which a car can safely negotiate a frictionless banked curve does not depend on the mass of the car. It depends on the angle of the bank, the radius of the curve, and the coefficient of static friction between the tires and the road surface.
What is the maximum speed with which a 1200- car can round a turn of radius 72 on a flat road if the coefficient of static friction between tires and road is 0.65?
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What factors have an effect on the maximum velocity at which a vehicule is able to travel on a curve that has no incline?
Factors that affect the maximum velocity on a curve with no incline include the radius of the curve, the coefficient of friction between the tires and the road, and the mass of the vehicle. A tighter curve radius, lower friction, or higher vehicle mass will decrease the maximum velocity the vehicle can safely travel around the curve without skidding.
What is the maximum speed a car can take in a 20m radius curve along a road if the coefficient of static friction between the tyres and the road is 0.60?
The maximum speed a car can take in a 20m radius curve is determined by the centripetal force required to keep the car on the curve. Using the formula Fc = mv^2/r, the maximum speed can be calculated to be approximately 22.58 m/s, or about 81.29 km/h.
If you know the coefficient of friction how do you find the maximum velocity to maintain a circular path at a given radius?
say mass(m) = 10 kg, radius(r) = 10 m, say friction coefficient = 0.5 force to break friction = 10 * 0.5 = 5 kgf = say 50 n to find acceleration required to produce this force use f=m*a, shuffle to a = f / m so a = 50 / 10 = 5 (m/s)/s, install in a = v^2 / r, so 5 = v^2 / 10, so 10 * 5 = v^2, so sq. root 50 = v, so v = 7.07 metres / second if friction coefficient and radius remain the same, altering the mass wont alter the velocity at breakaway point
If a curve with a radius of 60 m is properly banked for a car traveling 60 kmh what must be the coefficient of static friction for a car not to skid when travelling at 90 kmh?
To prevent skidding at 90 km/h, the car would need a coefficient of static friction of at least 0.25. This value can be calculated using the formula: coefficient of friction = tan(theta), where theta is the angle of banking. Given the curve radius, speed, and the formula, we can determine the necessary value for the coefficient of friction.
The maximum speed at which a car can safely negotiate a frictionless banked curve depends on all of the following except?
The maximum speed at which a car can safely negotiate a frictionless banked curve does not depend on the mass of the car. It depends on the angle of the bank, the radius of the curve, and the coefficient of static friction between the tires and the road surface.
What is the maximum speed with which a 1200-kg kg car can round a turn of radius 93.0m on a flat road if the coefficient of static friction between tires and road is 0.45?
The idea here is to: * Write an equation for the centripetal acceleration, using v squared / r. * Calculate the corresponding centripetal force, using Newton's Second Law (multiply the previous point by the mass). * Write an equation for the force of friction. * Equate the two forces, and solve.
A 200-kg car rounds a circular turn of radius 20 m If the road is flat and the coefficient of the friction between tires and road is 70 how fast can the car go without skidding?
define skidding.... 30mph.
Physics coefficient of friction radius of 60 m is properly banked for a car traveling 60 kmh what must be the coefficient of static friction for a car not to skid when travelling at?
The coefficient of static friction for a car not to skid when travelling at 60 km/hr on a banked curve of radius 60 m is 0.25. This is calculated using the formula: coefficient of static friction = tan(θ), where θ is the angle of banking. Given that the equation is properly banked, the angle of banking would be such that tan(θ) = V^2 / (R * g), where V is the velocity, R is the radius of the curve, and g is the acceleration due to gravity. Substituting the values, we get tan(θ) = (60 km/hr)^2 / (60 m * 9.8 m/s^2) = 0.25.
What is the maximum speed with which a 1200-kg car can round a turn of radius 80.0 rm m on a flat road if the coefficient of friction between tires and road is 0.65?
Friction = m Cf g centripetal force = mv^2/r maxium speed Ff = Fc mCfg = mv^2/r v=sqrt (Cf g r) v = sqrt (.65 *9.81 *80m) v = 22.58 m/s
What is the maximum speed with which a 1130 kg car can round a turn of radius 60 m on a flat road if the coefficient of friction between tires and road is 0.80?
m=1130kg r=60 m Friction coefficient= 0.80 Formula: v=(F*r/m)^1/2 where F is the normal force, r is the radius, and m is the mass. The equation is to the 1/2 power because the answer needs to be square rooted. In order to solve this equation, you need to calculate F which =mg (mass times value of gravity). The value of gravity is 9.80m/s F=1130kg*9.80m/s=11074 Newtons The value of F is now multiplied by the friction coefficient to determine the maximum friction force: Fmax=11074*.8=8859. 8859 is the value of FN that we can now plug into our equation below. so now we can solve the equation: v=((8859*60/1130))^1/2 v=21.68 meters/second or about 22 m/s This means that the car can travel as fast as about 22 meters/ second and stay on the curve without sliding off.
How long does it take for a solid to rest in a settling basin?
In theory - forever. In practice it will depend on many factors: friction coefficient, mass of object, radius of basin, initial conditions.
