The area enclosed on a velocity vs time graph represents the displacement or distance traveled by an object. Positive areas indicate motion in one direction, while negative areas indicate motion in the opposite direction. The greater the area, the greater the total displacement.
To determine velocity from an acceleration-time graph, you can find the area under the curve of the graph. This area represents the change in velocity over time. By calculating this area, you can determine the velocity at any given point on the graph.
The displacement of an object from a velocity-time graph can be determined by finding the area under the velocity-time graph. For example, the displacement over a certain time interval can be calculated by finding the area of the corresponding region under the velocity-time graph. This can be done by calculating the area of the trapezoid or rectangle formed by the graph.
No, displacement is the area under the velocity vs. time graph. The slope of a velocity vs. time graph represents acceleration.
The area under a velocity-time graph represents the displacement of an object. If the area is positive, the object is moving in the positive direction; if negative, the object is moving in the negative direction. The steeper the slope of the graph, the greater the velocity.
To find the position of an object from a velocity-time graph, you need to calculate the area under the curve of the graph. This area represents the displacement of the object.
To determine velocity from an acceleration-time graph, you can find the area under the curve of the graph. This area represents the change in velocity over time. By calculating this area, you can determine the velocity at any given point on the graph.
Area under velocity versus time graph(between two given instances of time i.e. two points on time axis) gives the displacement of the body( whose graph was plotted) between those two instances i.e. in that time interval. Area under velocity time graph can be found from definite integration if the graph is a curve. Note: Area under velocity versus time graph gives displacement not distance covered by body. Note: Area enclosed between the plotted curve and time axis is taken. For convenience time should be taken in the x-axis.
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
The displacement of an object from a velocity-time graph can be determined by finding the area under the velocity-time graph. For example, the displacement over a certain time interval can be calculated by finding the area of the corresponding region under the velocity-time graph. This can be done by calculating the area of the trapezoid or rectangle formed by the graph.
The area under the speed/time graph between two points in time is the distance covered during that time.
In a speed - time graph, the area under the line equals the distance traveled during the time interval A of ____ = L X W A of triangle = 1/2 bh
No, displacement is the area under the velocity vs. time graph. The slope of a velocity vs. time graph represents acceleration.
The area under a velocity-time graph represents the displacement of an object. If the area is positive, the object is moving in the positive direction; if negative, the object is moving in the negative direction. The steeper the slope of the graph, the greater the velocity.
Distance.
To find the position of an object from a velocity-time graph, you need to calculate the area under the curve of the graph. This area represents the displacement of the object.
The area under a position-time graph represents the displacement of an object. It is calculated by finding the area between the curve of the graph and the time axis. The units of the area will be in distance units (e.g., meters, kilometers).
The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)