The net force on the crate is 70 N to the left while it's moving to the left,
and 20 N to the right while it's moving to the right.
If the 100N force and the 50N force are acting on it at the same time,
then the net force on the crate is 20 N towards the left.
The net force is the difference between the two forces, so it would be 6 N (pulling force) - 5 N (pushing force) = 1 N to the right.
Use Newton's Second Law, F=ma. Solving for a: a = F/m (acceleration = force / mass). If the force is in Newton, and the mass in kilograms, acceleration will be in meters/second2.
The cart on the left will move because there is an unbalanced force acting on it, likely due to a force pushing it from the left. The cart on the right is likely not moving because the forces acting on it are balanced, resulting in no net force causing it to move.
An example of net force in real life is when you push a shopping cart in one direction while someone else simultaneously pushes it in the opposite direction. The resulting net force will determine the cart's overall motion.
F = m aa = F/m = 12/22 = 6/11 = 0.545 meter/sec2 (rounded)
The net force is the difference between the two forces, so it would be 6 N (pulling force) - 5 N (pushing force) = 1 N to the right.
Use Newton's Second Law, F=ma. Solving for a: a = F/m (acceleration = force / mass). If the force is in Newton, and the mass in kilograms, acceleration will be in meters/second2.
The cart on the left will move because there is an unbalanced force acting on it, likely due to a force pushing it from the left. The cart on the right is likely not moving because the forces acting on it are balanced, resulting in no net force causing it to move.
An example of net force in real life is when you push a shopping cart in one direction while someone else simultaneously pushes it in the opposite direction. The resulting net force will determine the cart's overall motion.
F = m aa = F/m = 12/22 = 6/11 = 0.545 meter/sec2 (rounded)
The work done by the person is calculated as the force applied multiplied by the distance the cart moves in the direction of the force. In this case, the work done would be 40 newtons x 10 meters = 400 joules.
The net force on the cart would be 0 Newtons because the forces pulling to the right and left are equal in magnitude but opposite in direction, resulting in a balanced force situation.
The cart's acceleration can be calculated using Newton's second law, which states that (F=ma) (force equals mass times acceleration). In this case, the force is 12 N and the mass is 22 kg. Therefore, the acceleration of the cart is (a = \frac{F}{m} = \frac{12 N}{22 kg} \approx 0.55 , m/s^2).
The force of friction will push the cart to the east, which is opposite to the direction the cart is being pushed. Friction always acts in the direction opposite to the direction of motion.
If a larger force is exerted on the loaded cart, the cart will accelerate in the direction of the force applied. This acceleration depends on the mass of the cart and the magnitude of the force. If the force is strong enough, it may even cause the cart to move uncontrollably or tip over.
If the force of friction acting on a cart on a ramp is exactly balanced by the force of gravity acting on the cart down the ramp, the cart will remain at a constant speed and not accelerate. This is an example of a state of equilibrium where the forces are balanced, resulting in no net force acting on the cart.
The effect is that the grocery cart moves around the aisles of the grocery store as the mommy directs it.