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The net force on the skateboard is 4 N. This is calculated using the equation F = m * a, where F is the force, m is the mass (2 kg), and a is the acceleration (2 m/s^2).
The net force on the skateboard can be found using Newton's second law, F = ma, where F is the force, m is the mass (2 kg), and a is the acceleration (2 m/s^2). Plugging in the values, we get F = 2 kg * 2 m/s^2 = 4 N. So, the net force on the skateboard is 4 Newtons.
The net force can be calculated using the formula: Net Force = Mass x Acceleration. In this case, the net force acting on the 250 kg trailer accelerating at 4 m/s² would be 1000 N (250 kg x 4 m/s²), directed in the direction of acceleration.
The net force acting on the ball is 3 N. This can be calculated using Newton's second law, F = m * a, where F is the force, m is the mass of the ball, and a is the acceleration. Substituting the values, F = 0.1 kg * 30 m/s^2 = 3 N.
The net force acting on a 1-kg freely falling object is equal to its weight, which is the force of gravity pulling it downward. This force is approximately 9.8 newtons (N) on Earth.
Yes, the net force on a 2-kg skateboard accelerating at a rate of 2 m/s² can be calculated using Newton's second law (F = ma). In this case, F = 2 kg × 2 m/s², which equals 4 N. Therefore, the net force acting on the skateboard is 4 Newtons.
The net force on the skateboard is 4 N. This is calculated using the equation F = m * a, where F is the force, m is the mass (2 kg), and a is the acceleration (2 m/s^2).
The net force on the skateboard can be found using Newton's second law, F = ma, where F is the force, m is the mass (2 kg), and a is the acceleration (2 m/s^2). Plugging in the values, we get F = 2 kg * 2 m/s^2 = 4 N. So, the net force on the skateboard is 4 Newtons.
The net force can be calculated using the formula: Net Force = Mass x Acceleration. In this case, the net force acting on the 250 kg trailer accelerating at 4 m/s² would be 1000 N (250 kg x 4 m/s²), directed in the direction of acceleration.
3000 N
Newton's 2nd law of motion: F = M AForce = (0.015 kg) x (12 m/s2) = 0.18 kg-m/s2 = 0.18 newton
How do you determine the net force on an object? Decide which direction is positive motion. Motion is the opposite direction is negative The forces must in a straight line!! Add all the forces in straight line acting on the object. Example To the right is positive A 5 N force pushes a 10 Kg object to the right. A 2 N force pushes the same 10 Kg object to the left. The 5 N forces is positive and the 2N force is negative Net force = +5 N - 2 N = + 3 N To determine the acceleration use Newton's 2nd law of motion F = Mass * acceleration + 3 N = 10 Kg * a a = 10 Kg ÷ + 3 N a = +3 ⅓ m/s^2 The positive sign means the object is accelerating to the right!! If the forces are not linear, you must use vectors, but the net force in any direction is still the sum of the vectors in that direction.
The net force acting on the ball is 3 N. This can be calculated using Newton's second law, F = m * a, where F is the force, m is the mass of the ball, and a is the acceleration. Substituting the values, F = 0.1 kg * 30 m/s^2 = 3 N.
The net force on the backpack can be calculated using Newton's second law, which states F = ma, where F is the net force, m is the mass, and a is the acceleration. Therefore, the net force on the backpack would be 6.0 N (12.0 kg * 0.5 m/s^2).
Force = (mass in kg)x(acceleration in m.s^-2)
The net force acting on a 1-kg freely falling object is equal to its weight, which is the force of gravity pulling it downward. This force is approximately 9.8 newtons (N) on Earth.
The cart is decelerating, not accelerating.