The output force is 100 N.
Work is force times distance - assuming the force is applied in the same direction as the movement.
The output force will be 100N, assuming the system is ideal with no energy losses. This is based on the principle of conservation of energy, where input energy equals output energy in an ideal system.
The work done is calculated using the formula: work = force x distance. In this case, the force is 100N and the distance is 5m. Therefore, the work done is 100N x 5m = 500 Joules.
The work done to push an object is calculated by multiplying the force applied by the distance over which it is applied. In this case, 100N of force is applied over a distance of 5 meters, resulting in 500 Joules of work done to push the object.
To calculate the work done, we need to consider the force applied by the girl minus the force of friction. The net force is 300N - 200N = 100N. Work done = force x distance. Therefore, the work done is 100N x 750m = 75,000 joules.
Work is force times distance - assuming the force is applied in the same direction as the movement.
The output force will be 100N, assuming the system is ideal with no energy losses. This is based on the principle of conservation of energy, where input energy equals output energy in an ideal system.
The work done is calculated using the formula: work = force x distance. In this case, the force is 100N and the distance is 5m. Therefore, the work done is 100N x 5m = 500 Joules.
175N
If the box is sliding along at a constant speed, the net force acting on the box is zero.If the net force was not zero, the box would either be speeding up or slowing down.Non-zero net forces acting on objects cause the objects to accelerate. Therefore, if the net forces is not zero, the velocity of the object could not be constant.
1N force is required to move a 1kg of weigt for 1m so for 100N force of resistance is producedRead more: http://wiki.answers.com/What_is_the_resistance_force_is_given_by_sand_if_a_mass_of_100kg_is_falling_from_a_height_of_1m_penetrates_the_sand_into_for_1m#ixzz1cMhEeFEI
The acceleration is 0. That also means that the net force is 0N since the gravity Force is 100N down and the bag of nails is 100N, the air resistance must be 100N up to balance it out and create the net force of 0N
The work done to push an object is calculated by multiplying the force applied by the distance over which it is applied. In this case, 100N of force is applied over a distance of 5 meters, resulting in 500 Joules of work done to push the object.
To calculate the work done, we need to consider the force applied by the girl minus the force of friction. The net force is 300N - 200N = 100N. Work done = force x distance. Therefore, the work done is 100N x 750m = 75,000 joules.
The acceleration is 0. That also means that the net force is 0N since the gravity Force is 100N down and the bag of nails is 100N, the air resistance must be 100N up to balance it out and create the net force of 0N
The efficiency of the lever can be calculated using the formula: Efficiency = (Output force × Output distance) / (Input force × Input distance). Plugging in the values given: Efficiency = (350N × 1m) / (100N × 5m) = 7/10 = 0.7 or 70%.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)