potential energy = m*g*h m=62kg g=9.81 m/s^2 h=410m multiply all those together and you get 249,370 Joules.
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
An electron may move to an electron shell farther out from the nucleus.
1 yes when electron moving in a shell 2 aeroplanes when moving in skies 3 when we are travelling in a bus or car
electrons are found in pairs
Momentum=35*500=17500Ns
electrons in the first electron shell have the lowest possible potential energy because YOUR MOM DROPPED U ON YOUR HEAD WHEN U WERE A BABY
bcoz the energy of bound system is always negative
the cannon breach is where the artillery shell is inserted for firing...................
The value of a 90mm cannon shell varies by its condition. As of 2014 these shells sell at auction for around 50.00.
Before the cannon is fired, the momentum is zero. So, after firing, the momentum must still be zero. The momentum of the shell is equal and opposite to that of the cannon, because there is an action and an equal reaction force. Since the momentum difference must be equal: (mv)cannon = (mv)shell Thus, (mv)c - (mv)s = 0 A simple way of looking at it is this is: If the shell is 100 times lighter than the cannon then the shell will move off 100 times faster than the cannon recoils. Remember that, in explosions, the lighter portion moves off faster than the heavier one.
The source of the explosion comes from the stored chemical potential energy within the shell. However, the laws of physics still apply to this situation. Energy will be conserved: the sum of the chemical energy released by the explosive and the kinetic energy of the shell before the explosion will always equal sum of the combined kinetic energy of the fragments and the heat, sound, and light energy released by the explosion. Momentum will be conserved: the added momentum vectors of all the shell fragments will equal the momentum of the shell before it exploded. The shell fragments will not all travel in the same direction.
An electron may move to an electron shell farther out from the nucleus.
a shell is une coquille, un coquillage (sea shell), une écaille (turtle), un obus (ammunition for a cannon)
This electron shell is near the atomic nucleus.
An Artillery piece (large cannon) or gun firing a large calibre shell. When the shell landed this would be an artillery explosion.
As from top to bottom on a periodic table one energy shell is added. Thus the distance between the electrons and the protons increase and the attraction force decreases. Then it becomes easier to get one electron out from the most outer shell. This is why the ionization potential decreases.
Electrons in the outermost energy shell (valence shell) have the most energy.