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What will be the power of convex lens having a focal length is 50 cm?
The power of a lens is given by the formula P = 1/f, where f is the focal length in meters. Converting 50 cm to meters, we get f = 0.5 m. Therefore, the power of a convex lens with a focal length of 50 cm is P = 1/0.5 = 2 diopters.
What is the magnification of a lens with a focal of 2 in?
The magnification of a lens depends on the object distance and image distance from the lens. The magnification formula is given by M = -image distance/object distance. Without knowing the object distance, it is not possible to calculate the magnification of the lens with a focal length of 2 inches.
Focal distance of a concave lens is always what?
To my understanding of psychology, the lens convexity in distant vision is increased in order to better take in the visual stimuli. To focus visual stimuli on the fovea (focus point) of the retina, the lens undergoes a process of adjusting called "accommodation," and it becomes more convex to ensure that distant objects reach the retina. A failure to properly accommodate leads to nearsightedness (faraway objects falling short of retina) or farsightedness (nearby objects falling past retina)
What is the focal length of a converging lens which produces a virtual image four time the size of the object the image being 15 cm from the lens?
Using the lens formula (1/f = 1/do + 1/di) and the magnification formula (m = -di/do) where m = -4, you can solve for the focal length (f). Given the object distance (do = -15 cm), you can calculate the focal length to be 10 cm.
What was the focal length when the radius of curvature was 0.70 m and index of refraction was 1.8?
The focal length of a lens is related to its radius of curvature and the index of refraction by the lensmaker's equation: [\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)] Given the radius of curvature (R = 0.70 , m) and the index of refraction (n = 1.8), you can calculate the focal length.
What will be the power of convex lens having a focal length is 50 cm?
The power of a lens is given by the formula P = 1/f, where f is the focal length in meters. Converting 50 cm to meters, we get f = 0.5 m. Therefore, the power of a convex lens with a focal length of 50 cm is P = 1/0.5 = 2 diopters.
What will be the magnification of a lens of 20D?
The magnification of a lens is calculated using the formula M = 1 + D/f, where M is the magnification, D is the lens power in diopters (20D in this case), and f is the focal length of the lens in meters. Without knowing the focal length of the lens, we cannot determine the exact magnification.
What is the magnification of a lens with a focal of 2 in?
The magnification of a lens depends on the object distance and image distance from the lens. The magnification formula is given by M = -image distance/object distance. Without knowing the object distance, it is not possible to calculate the magnification of the lens with a focal length of 2 inches.
Focal distance of a concave lens is always what?
To my understanding of psychology, the lens convexity in distant vision is increased in order to better take in the visual stimuli. To focus visual stimuli on the fovea (focus point) of the retina, the lens undergoes a process of adjusting called "accommodation," and it becomes more convex to ensure that distant objects reach the retina. A failure to properly accommodate leads to nearsightedness (faraway objects falling short of retina) or farsightedness (nearby objects falling past retina)
What is the focal length of a converging lens which produces a virtual image four time the size of the object the image being 15 cm from the lens?
Using the lens formula (1/f = 1/do + 1/di) and the magnification formula (m = -di/do) where m = -4, you can solve for the focal length (f). Given the object distance (do = -15 cm), you can calculate the focal length to be 10 cm.
What is the SI unit of converging ability of a lens?
Optical power (also referred to as dioptric power, refractive power, focusing power, or convergence power) is the degree to which a lens, mirror, or other optical system converges or diverges light. It is equal to the reciprocal of the focal length of the device.[1] The dioptre is the most common unit of measurement of optical power. The SI unit for optical power is the inverse metre (m−1).
The far point of myopia person is 85 cms in front of the eyes what is nature and power of the lens required to correct the vision?
The defect the person suffers from is myopia. 1/f=1/u+1/v 1/f=1/-85-1/infinity f=-85 cm =-0.85 m The power of the lens=1/f =1/-0.85 =-1.176 D Concave lens have negative focal length and are used for myopia. Thus the the lens that should be used to correct this defect is a concave lens of -1.176 D.
What was the focal length when the radius of curvature was 0.70 m and index of refraction was 1.8?
The focal length of a lens is related to its radius of curvature and the index of refraction by the lensmaker's equation: [\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)] Given the radius of curvature (R = 0.70 , m) and the index of refraction (n = 1.8), you can calculate the focal length.
What was the focal length when the eadius of curvature was 0.70 m and index of refrection was 1.8?
The focal length of a lens is related to its radius of curvature and refractive index by the lensmaker's formula: [ \frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) ] When the radius of curvature is 0.70 m and the refractive index is 1.8, the focal length can be calculated using this formula.
How is magnifying power of telescope and a microscope are a affected by increasing the focal length of their objectives?
The magnification of a telescope M is the the focal length of the objective Fo over the focal length of the eyepiece Fe so increasing the focal length of the objective increases the magnification. The magnification of a microscope M is approximately tube length L/Fo x 25/Fe. Therefore increasing the focal length of the objective reduces the magnification.
What is m to the 2 power plus m to the 3 power?
it depends on what m is.
What is m to the power of 4 divided by m to the power of six simplified?
it will be m to the power -2. assuming m as any variable.
