i dont really know--inertia is the thing that jerks you forward if the bus you are riding in suddenly stops and the period of a pendulum is how long it takes the pendulum to complete a full swing
"g" is (directly) proportional to the square root of the length of the pendulum. (at a constant small amplitude)
They determine the length of time of the pendulum's swing ... its 'period'.
-- friction in the pivot -- air moving past the pendulum -- the effective length of the pendulum -- the local acceleration of gravity
1. Length of the pendulum 2. acceleration due to gravity at that place
-- its length (from the pivot to the center of mass of the swinging part) -- the local acceleration of gravity in the place where the pendulum is swinging
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
For small angles, the formula for a pendulum's period (T) can be approximated by the formula:T = 2 * pi * sqrt(L/g), where L is the length of the pendulum length, and g is acceleration due to gravity. See related link for Simple Pendulum.
There's no relationship between the length of the pendulum and the number of swings.However, a shorter pendulum has a shorter period, i.e. the swings come more often.So a short pendulum has more swings than a long pendulum has in the same amountof time.
T=1/2l
t = 2*pi*sqrt(l/g) Where t is the period, l is the length and g is the accelaration due to gravity.
They determine the length of time of the pendulum's swing ... its 'period'.
Yes. Given a constant for gravity, the period of the pendulum is a function of it's length to the center of mass. In a higher gravity, the period would be shorter for the same length of pendulum.
The longer a pendulum is, the more time it takes a pendulum takes to complete a period of time. If a clock is regulated by a pendulum and it runs fast, you can make it run slower by making the pendulum longer. Likewise, if the clock runs slow, you can make your clock run faster by making the pendulum shorter. (What a pendulum actually does is measure the ratio between time and gravity at a particular location, but that is beyond the scope of this answer.)
The period of a pendulum is totally un-affected by the mass of the bob.The time period of pendulum is given by the eqn.T=2*PIE*(l/g)1/2 ;l is the length of pendulum;g is the acceleration due to gravity.'l' is the length from the centre of suspension to the centre of gravity the bob.ie.the length of the pendulum depends on the centre of gravity of the bob,and hence the distribution of mass of the bob.
-- friction in the pivot -- air moving past the pendulum -- the effective length of the pendulum -- the local acceleration of gravity
1/v = 2pi sqrt(l/g)
known to be seconds pendulum,the length would be almost 1m when acceleration due to gravity is 9.8m/s2
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).