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What is the size of the buoyant force that acts on a floating ball that normally weighs 5.1 N?
Wiki User
∙ 13y ago
We know that the F(buoyancy)=(Density) x g x (Volume)
Fb=D x g x V
Density =mass/volume, substitute D with m/v
The Equation should now read, Fb= m/v x g x V
You can now see that the Volume's will cancel out. Leaving us with
Fb= m x g
To solve for m, use F=ma
a= 9.8 or 10 Force is given as 26.0 N 26.0=10 x m
m=2.6 kg
Now use Fb= 2.6 x 10 Fb= 26 N
This is correct since we know that the Force of gravity must be equal and opposite to the Force of buoyancy so that the Net Force=0
Fb+Fg=0
26+(-26)=0
Hope this helped!
Wiki User
∙ 14y ago
Wiki User
∙ 13y agoIf the ball is floating, then the buoyant force on it 5.1 N.
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