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Earth;s Gravitational Acceleration is 9.8 m/s^(2)

Using the eq'n

a = (u - v)/t

a = 9/8 m/s^(2)

u = initial velocity of 0 m/s (lift off).

v = escape (final velicity)

t = time ( say 5 mins 300 s). (Probabky the time you can see it accelerating into space).

Hence

Algebraically rearranging

at = u - v

v = u - at.

v = 0 - (9.8 * 300 (

v = 9.8 300 = 2940 m/s

or

v = 2940 x 3600 / 1000

NB 3600 sec / hy

NNB 1000 m/ km

Hence

v = 10,500 km /hr.

This is not taking into consideration the mass of the rocket. When mass is included , although mass in reducing because of fuel combustion., a closer value is about 25,000 km/hr.

These are only hypothetical figures, but it gives an idea of the velocity required.

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lenpollock

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6mo ago

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