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What is the tension in the upper string and in the lower string if a 4.45 kg object is attached to a vertical rod by two strings and object rotates in a horizontal circle at constant speed 7.05 ms?
Wiki User
∙ 14y ago
Good For The Object. There is no question...
but if you're looking for the tension in the strings,
First draw a picture.
Next, Determine the radius. Take half the height entire object. This should give you a right triangle. Use pathegerian's theorema2+b2=c2 so (half the rod)2 + b2 = (length of string)2
Next, Find the angle between the string and the radius
sin-1(a/c) = angle
From there, Sum the forces in both the x and y directions
Fx= T1sin(A)-mg-T2sin(A) = 0
Fx= (T1-T2)sin(A) = mg
Fy= T1cos(A)+T2cos(A) = mv2/r
Fy= (T1+T2)cos(A) = mv2/r
Solve as much as you can for both Fx and Fy
Fx = T1-T2= #
Fy = T1+T2= #
Set the equations equal to each other to find a given T. Then solve for the other T.
Wiki User
∙ 14y ago
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