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You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 5 seconds?
The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.
What is the distance that the object travels in the first 5 seconds?
To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.
A race car accelerates from rest at a rate of 6 m s How fast will the car be going after 5 seconds?
The car's speed after 5 seconds can be calculated using the formula ( v = u + at ), where (v) is the final velocity, (u) is the initial velocity (0 m/s in this case), (a) is the acceleration (6 m/s(^2)), and (t) is the time (5 seconds). Plugging in the values gives (v = 0 + 6 \times 5 = 30 ) m/s. Thus, the car will be going 30 m/s after 5 seconds.
If a car is approaching a stop light and slows from 20 meters per second to a stop in 5 seconds what is the acceleration?
The acceleration of the car can be found using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 0 m/s (stopped), the initial velocity is 20 m/s, and the time is 5 seconds. So, the acceleration would be (0 m/s - 20 m/s) / 5 s = -4 m/s^2.
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
11 ms in 5 seconds what is the acceleration?
It depends on what the initial velocity was. If it was 0, then: 11-0 = 2.2 m/s squared 5
What velocity does the student have after five seconds?
Velocity increases after 5 seconds
What is a cars acceleration if it travels 0 to 55 miles per hour in 6 seconds?
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
What is the velocity of a car that is drives 10 meters in 5 seconds?
The velocity of the car can be calculated using the formula: velocity = distance/time. In this case, the car travels 10 meters in 5 seconds, so the velocity is 10 meters ÷ 5 seconds = 2 meters per second. Therefore, the car's velocity is 2 m/s.
You throw a ball straight up with a velocity of 40 meters per second. What is the ball's velocity after 5 seconds?
The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.
What is the accelaration 0 to 60 mph in seconds for 2010 Chevrolet camaro ss?
Between 4.5-5 seconds
What is the distance that the object travels in the first 5 seconds?
To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.
A race car accelerates from rest at a rate of 6 m s How fast will the car be going after 5 seconds?
The car's speed after 5 seconds can be calculated using the formula ( v = u + at ), where (v) is the final velocity, (u) is the initial velocity (0 m/s in this case), (a) is the acceleration (6 m/s(^2)), and (t) is the time (5 seconds). Plugging in the values gives (v = 0 + 6 \times 5 = 30 ) m/s. Thus, the car will be going 30 m/s after 5 seconds.
If a car is approaching a stop light and slows from 20 meters per second to a stop in 5 seconds what is the acceleration?
The acceleration of the car can be found using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 0 m/s (stopped), the initial velocity is 20 m/s, and the time is 5 seconds. So, the acceleration would be (0 m/s - 20 m/s) / 5 s = -4 m/s^2.
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
A ball starts at rest accelerates uniformly and travels 250m in 5 seconds What is the final velocity and the acceleration of the ball?
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
What is the acceleration of an object that starts stopped and after 5 seconds is going 25mm per hour?
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
